The acceleration of the first block (4 kg) is -9.8 m/s².
The given parameters:
- <em>Mass of the first block, m₁ = 4.0 kg</em>
- <em>Mass of the second block, m₂ = 2.0 kg</em>
The net force on the system of the two blocks is calculated as follows;
where;
- <em>T </em><em>is the tension in the connecting string due weight of the first block</em>
Thus, the acceleration of the first block (4 kg) is -9.8 m/s².
Learn more about net force on two connected blocks here: brainly.com/question/13539944
Answer:
time of collision is
t = 0.395 s
so they will collide at height of 5.63 m from ground
Explanation:
initial speed of the ball when it is dropped down is
similarly initial speed of the object which is projected by spring is given as
now relative velocity of object with respect to ball
now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m
Now the height attained by the object in the same time is given as
so they will collide at height of 5.63 m from ground
Explanation:
it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f. Waves of different wavelengths.
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