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kolbaska11 [484]
3 years ago
10

A soccer player kicks a ball horizontally at 28 m/s from a bridge and hits the ground after 1.5 s. What is the range of the ball

?
Physics
1 answer:
Lelu [443]3 years ago
8 0

Answer:

42

Explanation:

range of ball = u×t

= 28×1.5

=42

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Seasons are caused by differences in daylight, temperature, and weather patterns due to :
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65. A length of wire is bent into a closed loop and a magnet is plunged into it, inducing a voltage and, consequently, a current
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Answer:

Resistance of the second wire is twice the first wire.

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As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.

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A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position
irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

  • <em>Mass of the ball, m = 2.4 kg</em>

<em />

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz

The angular frequency of the oscillation is calculated as follows;

\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s

The force constant of the spring is calculated as follows;

\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m

Learn more about general wave equation here: brainly.com/question/25699025

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What is a source of AC current
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hope this helps loves
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