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Yuki888 [10]
3 years ago
15

Two spheres of the same size and mass roll down an incline. Sphere A is hollow and Sphere B is solid with uniform density. Which

reaches the bottom of the incline first?
Make sure to EXPLAIN your answer!

(a) Sphere A
(b) Sphere B
(c) At the same time.
Physics
1 answer:
sweet [91]3 years ago
8 0
If the spheres are have to have the same and the same size, it is expected that they will have the same surface area. The only factor that affects the descent of the object through gravity on Earth is the surface area that is exposed to the resistance of air. For this case, it is expected that they will reach the bottom of the inclined plane together. The answer is C. 
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Which one of the following is the correct option for fill in the
serg [7]

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mechanical advantage!

Explanation:

The Mechanical advantage of a machine is the factor by which the machine changes the input force.

When a a machine multiplies an input force, that's called a mechanical advantage.

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Defenition of Mechanical Advantage

brainly.com/question/16617083?referrer=searchResults

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Hope this helps! <3

5 0
3 years ago
A ball is thrown vertically upwards with an initial velocity of 20.00 m/s. Neglecting air resistance, how long is the ball in th
algol [13]

Answer:

1) The greatest height attained by the ball equals 20.387 meters.

2) The time it takes for the ball to reach 15 meters approximately equals 1 second.

Explanation:

The greatest height will be attained when the ball stop's in the air and starts falling back to the earth.

thus using third equation of kinematics we obtain the height attained as

v^2=u^2+2as

where

'v' is the final speed of the ball

'u' is the initial speed of the ball

'a' is the acceleration that the ball is under which in this case equals 9.81 m/s^{2}

's' is the distance it covers

Thus for maximum height applying the values in the equation we get

0=20^{2}-2\times 9.81\times h\\\\\therefore h=\frac{20^{2}}{2\times 9.81}=20.387meters

Using the same equation we can find the speed of the ball when it reaches 15 meters of height as  

v^2=20^{2}-2\times 9.81\times 15\\\\v^{2}=105.7\\\\\therefore v=10.28m/s

the time it takes to reduce the velocity to this value can be found by first equation of kinematics as

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4 0
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