Complete the square to find the vertex of this parabola. x2-16y-4x-12=0
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You are looking for the shaded region that would be contained in both of the inequalities.
You have:
If you graph an shade the correct half-plane for those equations, you will see there is a triangular region on the left side of the first quadrant.
You have:
If you graph an shade the correct half-plane for those equations, you will see there is a triangular region on the left side of the first quadrant.