Question

Complete the square to find the vertex of this parabola. x2-16y-4x-12=0

Answer 1

Answer:

Step-by-step explanation:

x^2-16y-4x-12=0

Transpose and separate x and y

16y = x^2-4x-12

16y = (x^2-4x+4) -16

16y = (x-2)^2 -16

y = (1/16)(x-2)^2 -1

This means that the vertex is at

(x-2)=0 or x=2

y = -1

=> vertex (2,-1)