Someone plz help me fast for my exam

In the diagram, WZ=StartRoot 26 EndRoot.

gogolik [260]

Answer:

$P = 8 + 2\sqrt{26}$

Step-by-step explanation:

Given

$W = (-2, 4)$

$X = (2, 4)$

$Y = (1, -1)$

$Z = (-3,-1)$

Required

The perimeter

First, calculate the distance between each point using:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2$

So, we have:

$WX = \sqrt{(-2- 2)^2 + (4-4)^2 } =4$

$XY = \sqrt{(2- 1)^2 + (4--1)^2 } =\sqrt{26}$

$YZ = \sqrt{(1- -3)^2 + (-1--1)^2 } =4$

$ZW = \sqrt{(-3--2)^2 + (-1-4)^2 } =\sqrt{26}$

So, the perimeter (P) is:

$P = 4 + \sqrt{26} + 4 + \sqrt{26}$

$P = 8 + 2\sqrt{26}$

8 0

2 years ago

I really don't understand my teacher , can anyone here help me out please

zzz [600]

56 is what I got.

Hope this helps

6 0

3 years ago

Read 2 more answers

The little Mexican restaurant sells only two kinds of beef burritos mucho beef sandwich Lucho beef last week the restaurant orde

Finger [1]

Answer:

Cost of a single Mucho beef burrito: $\$5.5$

Cost of a double Mucho beef burrito: $\$6.5$

Step-by-step explanation:

<h3> The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>

Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.

Set a system of equations:

$\left \{ {{16x+22y=231} \atop {x=y-1}} \right.$

To solve this system you can apply the Substitution Method:

1. Substitute the second equation into the first equation and solve for "y":

$16(y-1)+22y=231\\\\16y-16+22y=231\\\\38y=231+16\\\\y=\frac{247}{38}\\\\y=6.5$

2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":

$x=6.5-1\\\\x=5.5$

5 0

3 years ago

The arrival time of a professor to her office is uniformly distributed in the interval between 8 and 9 A.M. Find the probability

NeTakaya

Answer:

0.025

Step-by-step explanation:

Given that the arrival time of a professor to her office is uniformly distributed in the interval between 8 and 9 A.M.

If the professor did not arrive till 8.20 he will arrive between 8.21 and 8.40

Hence probability for arriving after 8.20 is 1/40

Prob he arrives at exactly 8.21 is 1/60

To find the probability that professor will arrive in the next minute given that she has not arrived by 8: 20.

= Prob that the professor arrives at 8.21/Prob he has not arrived by 8.20

This is conditional probability and hence

= $P(professor arrives at 8.21)/P(professor arrives after 8.20)\\= \frac{\frac{1}{60} }{\frac{40}{60} } \\=\frac{1}{40} \\=0.025$

7 0

3 years ago

Identify any solutions to the system given below. 2x + y = 5 3y = 15 – 6x (6, –7) (2, 1) (–2, –9) (–4, 13)

sashaice [31]

Answer:

The answer (2, 1), (-4,13), (6,-7)

Step-by-step explanation:

Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2

1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)

Equation 1

2(2)+1=5 therefor it holds

Equation 2

3(1)=15-(6×2) also holds

2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)

Equation 1

2(6)+(-7)=5

5=5 holds

Equation 2

3(-7)=15-(6×6)

-21=-21 also holds

3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)

Equation 1

2(-4)+13=13-8=5 holds

Equation 2

3(13)=15-(6×-4)=39 also holds

4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)

Equation 1

2(-2)+(-9)=-4-9=-13≠5 does not hold

Equation 2

3(-9)≠15-(6×-2)

-27≠27 does not hold

The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given

8 0

3 years ago

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