So like my brother did the math but we got something that wasn’t up there lol. but the closest one is 300
Answer:
We have to find point that partition line segment AB with end points (-5,3) (-1,-5) in ratio 1:3
Assume (-5,3) as ( a,b)
Assume (-1,-5) as (c,d)
Assume ratio 1:3 as m:n
Step-by-step explanation:
Remember this formula
Partition point =( mc + na)/m+ n , ( md+ nb)/m+n
=[ (1)(-1)+ 3(-5)]/1+3, ( 1(-5) + 3(3))/1+3
= -1 -15)/4,( -5 + 9)/4
= -16/4, 4/4
= -4, 1


Positive sine, negative tangent, means we have a negative cosine. We're talking about the second quadrant.



We know it's negative,

Answer: -(1/3)√5
Answer:<em>Exactly one solution.</em>
Step-by-step explanation:
- 32 +9 – 2x = -12 – 5x
1.Add numbers
-23 - 2x= -12-5x
2.Rearrange terms
-2x - 23 = -12 - 5x
3. Rearrange terms
-2x - 23 = -5x-12
4. Add 23 to both sides of the equation
-2x-23+23= -5x-12+23
5.Simplify
-2x= -5x+11
6.Add 5x to both sides of the equation
-2x+5x=-5x+11+5x
7.Simplify
3x=11
8.Divide both sides of the equation by the same factor
= 
9.Simplify and Solution
x= 
The other endpoint would be (4,1)