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2 years ago

Which expressions are equivalent to 24 + 8? Choose ALL that apply,

Mathematics

2 answers:

Marrrta [24]2 years ago

7 0

Answer:

24 + 8 = 32

To find the result of the other answers, you should know by now that you the the “()” first, ill help you real quick!!

Step-by-step explanation:

2(12+8) = 12+8 = 20 x 2 = 40 - this is not the one

4(6+2) = 6 + 2 = 8 x 4 = 32 - This one is a correct one

2(12+4) = 12 + 4 = 16 x 2 = 32 - Here is another good one

6(4+2) = 4 + 2 = 6 x 6 = 36 - this one is incorrect

3(8+2) = 8 + 2 = 10 x 3 = 30 - this is incorrect

8(3+1) = 3 + 1 = 4 x 8 = 32 - this one is also correct

zepelin [54]2 years ago

4 0

Answer:
4(6+2)
2(12+4)
8(3+1)
Hope that helps :)

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I have an assignment and I am having trouble with it. Can someone please help ASAP???

bezimeni [28]

Answer:

A) Find the sketch in attachment.

In the sketch, we have plotted:

- The length of the arena on the x-axis (90 feet)

- The width of the arena on the y-axis (95 feet)

- The position of the robot at t = 2 sec (10,30) and its position at t = 8 sec (40,75)

The origin (0,0) is the southweast corner of the arena. The system of inequalities to descibe the region of the arena is:

$0\leq x \leq 90\\0\leq y \leq 95$

Since the speed of the robot is constant, it covers equal distances (both in the x- and y- axis) in the same time.

Let's look at the x-axis: the robot has covered 10 ft in 2 s and 40 ft in 8 s. There is a direct proportionality between the two variables, x and t:

$\frac{10}{2}=\frac{40}{8}$

So, this means that at t = 0, the value of x is zero as well.

Also, we notice that the value of y increases by $\frac{75-30}{8-2}=7.5 ft/s$ (7.5 feet every second), so the initial value of y at t = 0 is:

$y(t=0)=30-7.5\cdot 2 =15 ft$

So, the initial position of the robot was (0,15) (15 feet above the southwest corner)

The speed of the robot is given by

$v=\frac{d}{t}$

where d is the distance covered in the time interval t.

The distance covered is the one between the two points (10,30) and (40,75), so it is

$d=\sqrt{(40-10)^2+(75-30)^2}=54 ft$

While the time elapsed is

$t=8 sec-2 sec = 6 s$

Therefore the speed is

$v=\frac{54}{6}=9 ft/s$

The equation for the line of the robot is:

$y=mx+q$

where m is the slope and q is the y-intercept.

The slope of the line is given by:

$m=\frac{75-30}{40-10}=1.5$

Which means that we can write an equation for the line as

$y=mx+q\\y=1.5x+q$

where q is the y-intercept. Substituting the point (10,30), we find the value of q:

$q=y-1.5x=30-1.5\cdot 10=15$

So, the equation of the line is

$y=1.5x+15$

By prolonging the line above (40,75), we see that the line will hit the north wall. The point at which this happens is the intersection between the lines

$y=1.5x+15$

and the north wall, which has equation

$y=95$

By equating the two lines, we find:

$1.5x+15=95\\1.5x=80\\x=\frac{80}{15}=53.3 ft$

So the coordinates of impact are (53.3, 95).

The distance covered between the time of impact and the initial moment is the distance between the two points, so:

$d=\sqrt{(53.5-0)^2+(95-15)^2}=95.7 ft$

From part B), we said that the y-coordinate of the robot increases by 15 feet/second.

We also know that the y-position at t = 0 is 15 feet.

This means that the y-position at time t is given by equation:

$y(t)=15+7.5t$

The time of impact is the time t for which

y = 95 ft

Substituting into the equation and solving for t, we find:

$95=15+7.5t\\7.5t=80\\t=10.7 s$

The path followed by the robot is sketched in the second graph.

As the robot hits the north wall (at the point (53.3,95), as calculated previously), then it continues perpendicular to the wall, this means along a direction parallel to the y-axis until it hits the south wall.

As we can see from the sketch, the x-coordinate has not changed (53,3), while the y-coordinate is now zero: so, the robot hits the south wall at the point

(53.3, 0)

The perimeter of the triangle is given by the sum of the length of the three sides.

- The length of 1st side was calculated in part F: $d_1 = 95.7 ft$

- The length of the 2nd side is equal to the width of the arena: $d_2=95 ft$

- The length of the 3rd side is the distance between the points (0,15) and (53.3,0):

$d_3=\sqrt{(0-53.3)^2+(15-0)^2}=55.4 ft$

So the perimeter is

$d=d_1+d_2+d_3=95.7+95+55.4=246.1 ft$

The area of the triangle is given by:

$A=\frac{1}{2}bh$

where:

$b=53.5 ft$ is the base (the distance between the origin (0,0) and the point (53.3,0)

$h=95 ft$ is the height (the length of the 2nd side)

Therefore, the area is:

$A=\frac{1}{2}(53.5)(95)=2541.3 ft^2$

The percentage of balls lying within the area of the triangle traced by the robot is proportional to the fraction of the area of the triangle with respect to the total area of the arena, so it is given by:

$p=\frac{A}{A'}\cdot 100$

where:

$A=2541.3 ft^2$ is the area of the triangle

$A'=90\cdot 95 =8550 ft^2$ is the total area of the arena

Therefore substituting, we find:

$p=\frac{2541.3}{8550}\cdot 100 =29.7\%$

4 0

3 years ago

HELP PLEASE!!! I NEED THIS NOWWWWW!!

Ugo [173]

Part A - linear functions change at a constant rate.. while exponential functions change at a constant percent rate... that sounds the same but it's not. A linear function will go up (or down) the same amount when the time period is the same... like up 1,000 more visitors every month... if this happens, when you subtract the visitors for month 10-month 9, you will get the same answer as when you subtract he visitors for month 9-month 8.

An exponential function will go up by the same % when the time period is the same... so it'd be like if it went from 1,000 to 1,100 (that's up 100, which is 10% of 1,000) and then from 1,100 to 1,210 (that's up by 110, which is 10% of 1,100). If this happens you get the same answer when you divide the visitors for month 10 by the visitors from month 9 as you get when you divide the visitors for month 9 by the visitors from month 8. (sometimes because of decimals you only get really really close to the same but that counts).

This one is exponential because dividing gets you around 2.09 every time

Part B

Since dividing # of visitors by the # from the month before gets you around 2.09 each time, we multiply that by 100 to get the % version of the decimal.

So that's 209%... but that's not how much it changes by or grows by... that's what it ends up. It goes from itself (100%) to a bigger # (209%).. that's a 209-100 = 109% increase each month.

Part C

you need to think a little bit about what's going on in class.... becasue there are a bunch of different ways to do this. Sometimes you make an equation, sometimes you work backwards.

Here's one way... since multiplying visitors from week 8 by 2.09 gets you week 9 visitors.. and multipliying week 9 visitors by 2.09 gets you week 10... etc.... we can go backwards...

Week 7 visitors times 2.09 would equal the week 8 visitors

so, w(2.09)=5.74

if we divide both sides by 2.09 we get w is equal to about 2.7464... so the week 7 visitors is about 2.7464 (thousands) or 2,746.

Hope that helps

6 0

3 years ago

F(x) -<br> х3-14.х<br> 16x<br> 3х3 + 6x2_9x<br> Чx

andrew-mc [135]

Answer:

wrong❌❌

question

wrong❌❌

question

8 0

2 years ago

What value of b will cause the system to have an infinite number of solutions?

garri49 [273]

In order for the system to have an infinite number of solutions, both equations must be identical. So, the value of b must be 6

3 0

2 years ago

What is 497÷2 (Use long division on a piece of paper) Explain how you figured this out clearly so I can play along because I won

erma4kov [3.2K]

Dividing 2 into 4 you would get 2 and dividing it into 9 you would get 4 since you can't divide it into 9 so when you subtract that (9-8) you would get 1 you place a decimal and bring down a zero to get 10 then you would get 5 the answer would be 248.5

8 0

3 years ago