Answer:
when they cross u should get a perfect solution of (2,6)
Answer:
) See annex
b) See annex
x = 0,5 ft
y = 2 ft and
V = 2 ft³
Step-by-step explanation: See annex
c) V = y*y*x
d-1) y = 3 - 2x
d-2) V = (3-2x)* ( 3-2x)* x ⇒ V = (3-2x)²*x
V(x) =( 9 + 4x² - 12x )*x ⇒ V(x) = 9x + 4x³ - 12x²
Taking derivatives
V¨(x) = 9 + 12x² - 24x
V¨(x) = 0 ⇒ 12x² -24x +9 = 0 ⇒ 4x² - 8x + 3 = 0
Solving for x (second degree equation)
x =[ -b ± √b²- 4ac ] / 2a
we get x₁ = 1,5 and x₂ = 0,5
We look at y = 3 - 2x and see that the value x₂ is the only valid root
then
x = 0,5 ft
y = 2 ft and
V = 0,5*2*2
V = 2 ft³
The answer is 60 feet.
Step by step explanation:
The area of a triangle is Area= base x height divided by 2.
Solve for the base:
Base= 2* area/ height and plug in the data:
Base= 2* 600/20
Final answer:
Base: 60 feet.
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2


Take the square of this result, to give k


Substitute 121 for k
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
The expression can be factorized as follows;




<em>Hence, the quadratic expression is </em>
<em></em>
Answer:
Step-by-step explanation: -4.5=a-8
1. add 8 to both sides -4.5+8= 3.5
2. since you added 8 to negative 8 you get zero so it just goes away
3. ANSWER= 3.5=a