Question

Find three consecutive even integers such that six times the sum of the first and the third is twenty - four greater than eleven times the second .

Answer 1

Answer:

1st = 22

2nd = 24

3rd = 26

Step-by-step explanation:

1st = x

2nd = x +2

3rd = x + 4

6(x + x + 4) = 24 + 11(x + 2)

6(2x + 4) = 24 + 11x + 22

12x + 24 = 46 + 11x

x + 24 = 46

x = 22

x + 2 = 24

x + 4 = 26