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3 years ago

10

Find three consecutive even integers such that six times the sum of the first and the third is twenty - four greater than eleven

times the second .

1 answer:

dedylja [7]3 years ago

8 0

Answer:

1st = 22

2nd = 24

3rd = 26

Step-by-step explanation:

1st = x

2nd = x +2

3rd = x + 4

6(x + x + 4) = 24 + 11(x + 2)

6(2x + 4) = 24 + 11x + 22

12x + 24 = 46 + 11x

x + 24 = 46

x = 22

x + 2 = 24

x + 4 = 26

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3 years ago

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vazorg [7]

Answer:

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Step-by-step explanation:

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3 years ago

Solve the following inequality. |3n-2|-2<1

disa [49]

Answer: $\frac{-1}{3}$ < n < $\frac{5}{3}$

<u>Step-by-step explanation:</u>

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| 3n - 2 | < 3

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Interval Notation: $(\frac{-1}{3},$ $\frac{5}{3})$

Graph: $\frac{-1}{3}$ o--------------------o $\frac{5}{3}$

7 0

3 years ago

Read 2 more answers

If ln(4x+y)=2x-3,then dy/dx=

Viktor [21]

$\ln(4x+y)=2x-3$

Differentiate both sides wrt $x$ :

$\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}$

By the chain rule, we get

$\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2$

$\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2$

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4 0

3 years ago

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grin007 [14]

Answer:

The polynomial is 2 x² - 2x + 7

Step-by-step explanation:

Given polynomial

(8 x² + 9 ) - (6x² +2x +2)

= 8 x² +9 - 6x² - 2x -2

= 8x² - 6x² - 2x + 9-2

= 2 x² - 2x + 7

The polynomial is 2 x² - 2x + 7

5 0

3 years ago