Find three consecutive even integers such that six times the sum of the first and the third is twenty - four greater than eleven
times the second .
1 answer:
Answer:
1st = 22
2nd = 24
3rd = 26
Step-by-step explanation:
1st = x
2nd = x +2
3rd = x + 4
6(x + x + 4) = 24 + 11(x + 2)
6(2x + 4) = 24 + 11x + 22
12x + 24 = 46 + 11x
x + 24 = 46
x = 22
x + 2 = 24
x + 4 = 26
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