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2 years ago

1 page for every 3 students is a unit rate or rate

Mathematics

1 answer:

mixas84 [53]2 years ago

8 0

I think the answer to this is a rate

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HELP QUICK PLEASE 20 POINTS

trasher [3.6K]

Answer:

-2

Step-by-step explanation:

-5n + 18

where n is the number of the term

4 0

3 years ago

Read 2 more answers

Which function in vertex form is equivalent to f(x) = x2 + 8 – 16x? f(x) = (x – 8)2 – 56 f(x) = (x – 4)2 + 0 f(x) = (x + 8)2 – 7

kkurt [141]

Answer:

f(x) = x² + 8 - 16x

= x² - 16x + 8

= (x² - 16x + 64) - 64 + 8

= (x + 8)² - 56

4 0

3 years ago

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CALCULATOR

Drupady [299]

Answer: $d(r) = 5(0.87)^r$

Step-by-step explanation:

7 0

2 years ago

What is the difference between the median and the range in the data set shown below?

Snezhnost [94]

Median is 7, two numbers in the middle is 8 and 6, 8+ 6 = 14 divided by 2 is 7.

Range is largest number minus the smallest number. Largest number is 13 and smallest number is 1. 13-1 equals 12. Range is 12.

12 - 7 = 5 answer is 5

8 0

2 years ago

Read 2 more answers

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

2 years ago