All categories

3 years ago

Which gives the area of a rhombus with sides of length 10 in, and longer

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

Area of rhombus = 96 inch²

Step-by-step explanation:

Given:

Side length of rhombus = 10 inch

Length of longer diagonal = 16 inch

Find:

Area of rhombus

Computation:

We know that, diagonals of rhombus perpendicular bisect each other

So,

Half of small diagonal = √Side length of rhombus² - Half length of longer diagonal²

Half of small diagonal = √10² - 8²

Half of small diagonal = √100 - 64

Half of small diagonal = √36

Half of small diagonal = 6 inch

Length of smaller diagonal = 2 x 6

Length of smaller diagonal = 12 inch

Area of rhombus = (Product of diagonals)/2

Area of rhombus = (16 x 12)/2

Area of rhombus = 96 inch²

You might be interested in

ASAP HELP HELP NEED HELP FAILING

frez [133]

For the first question, you will write a ratio of 1/2 oz:10 pounds. Please see the attached picture. There are 9 groups of 10 oz in 90 oz, so you will need 9 groups of the amount of medicine too!

For the second question, you need to understand that the exponent (2^3) must be evaluated first because all forms of multiplication/ groupings comes first before adding or subtracting.
Exponents are a way of showing repeated multiplication, so it is done first.

3 0

3 years ago

Write a fraction equivalent to 4/18

marysya [2.9K]

Answer:

Its 2/9, sorry I can't show the explanation I have to do my work.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

4n+1=25<br>Please help with an explanation

dlinn [17]

Answer:

n = 6

Step-by-step explanation:

To isolate n, subtract 1 from both sides:

4n + 1 = 25

4n = 24

Then divide by 4 on both sides:

4n = 24

n = 6

Hope this helped :)

4 0

2 years ago

Read 2 more answers

Which line plot displays a data set with an outlier?<br><br> Plz answer quickly!

iren2701 [21]

The answer is the first data set because remember, an outlier is a number in a data set that is extremely far away from all of the other numbers.

You can easily tell which one is the outlier, the first data set's outlier is 13, because it is was placed so far away from the other data points.

We know that the first data set is correct because all of the other data sets have numbers that are clustered together.

~Hope I helped!~

7 0

3 years ago

the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume

zhuklara [117]

Given:
Population proportion, $\mu _{p}$ = 57% = 0.57
Population standard deviation, σ = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
$SE_{p} = \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783$

The confidence interval is
$\hat{p} \pm z^{*}SE_{p}$
where
$\hat{p}$ = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)

Answer: Between 0.417 and 72.4), or between (41% and 72%)

8 0

3 years ago