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trasher [3.6K]
2 years ago
15

Brian deposits $7000 into an account that pays simple interest at an annual rate of 3%. He does not make any more deposits. He m

akes no withdrawals until the end of 5 years when he withdraws all the money. Answer the following questions. If necessary, refer to the list of financial formulas. (a) How much total interest will Brian earn? $ (b) What will the total amount in the account be (including interest)?
Mathematics
1 answer:
Andre45 [30]2 years ago
4 0

Answer:

A)1050

B)8050

Step-by-step explanation:

to find interest we use the formula A= P(1+rt) where P is the initial investment, r is the rate percent, and t is the time interval

for this question we have A=7000(1+3(5)) which gives 8,050 dollars which is the answer to part B

for part A we simply subtract the answer from B from the initial investment so 8050 - 7000 = 1050 made from interest

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y=3x

Step-by-step explanation:

In this case, the ratio between sugar and water is 0.5 : 1.5 or 1 : 3.

That means that you need three cups of water for every cup of sugar.

In order to put this into an equation, the slope would be 3/1 or simply 3, and the y-intercept is 0. Even if you used the 0.5 : 1.5 ratio, the slope would be the same since 1.5 / 0.5 = 3.

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Write an inequality to represent the graph
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Answer:

its C. i hope this helps good luck and don't forget to thank and the brainly

Step-by-step explanation:

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3 years ago
Find the slope of the line which is perpendicular to a line having a slope of 5/7
erica [24]

Answer:

-7/5

Step-by-step explanation:

5/7

= -7/5

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3 years ago
Which number is written in scientific notation?
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4.5X10^-3

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8 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
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