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Flura [38]
3 years ago
10

A line passes through the point (6,-1) and is perpendicular to the line with equation -2x + 3y = -6.

Mathematics
2 answers:
harina [27]3 years ago
7 0

TyryyAnswer:

Step-by-step explanation:

Bjmed

DENIUS [597]3 years ago
4 0
Hi I don’t see what you want
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How do i write 2 perfect squares that each have a value greater then 100 and less that 200
nordsb [41]

Just start squaring numbers! 10² = 100, so to find perfect squares bigger than that, we can just increase the base. 11² = 121, and 12² = 144, and both of those meet our requirements, so we could choose 121 and 144 as our examples.

8 0
3 years ago
What is the equation of the line
LenKa [72]

Answer:

y=0

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Are these polygons similar ? Explain why or why not.
expeople1 [14]

Answer:

Yes, the polygons are similar.

Step-by-step explanation:

A similar polygon is a polygon that shares the same scale factor as another polygon. A scale factor is a number you can multiply each side by to get a similar figure,


Step 1:

Divide a few of the sides. You do not need to divide every side to find the ratio, but do at least 2 or 3 to guarantee that the scale factor remains the same throughout the sides. Let’s divide a few pairs of sides.

27/18=1.5

30/20=1.5

21/14=1.5

Step 2:

To really be safe, even though we can clearly tell this is a similar figure, is we can multiply each side on the right figure by 1.5, our scale factor, and see if we generate the sides on the left figure.

18*1.5=27

20*1.5=30

14*1.5=21

And this is why the polygons are similar :)

4 0
2 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
3 years ago
Given: (↔AB) ║ (↔CD)
nordsb [41]
1) m = y2 - y1/x2 - x1
y = mx + b
m = 7 - 0/3 - 8
y = -7/5x + 11.2
2) y= -7/5x + 12
(the slope or m stays the same because the two equations are parallel)
8 0
3 years ago
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