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GarryVolchara [31]

3 years ago

11

Given: (↔AB) ║ (↔CD)

1 answer:

nordsb [41]3 years ago

8 0

1) m = y2 - y1/x2 - x1
y = mx + b
m = 7 - 0/3 - 8
y = -7/5x + 11.2
2) y= -7/5x + 12
(the slope or m stays the same because the two equations are parallel)

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PLEASE CAN SOMEONE find the value of the trigonmetric ratio

VashaNatasha [74]

For this case we have the following trigonometric relationship:
sine (x) = C.O / h
Where,
x: angle
C.O: opposite leg
h: hypotenuse
Substituting values:
sine (C) = 9/41
Answer:
the value of the trigonometric ratio is:
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5 0

3 years ago

7. Subtract the polynomials:<br> 5x2 + 4x + 1 and x2 + 3x - 4

Colt1911 [192]

Answer:

4x²+x+5.

Step-by-step explanation:

5x²+4x+1-(X²+3x-4).

5x²+4x+1-x²-3x+4.

5x²-x²+4x-3x+1+4.

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3 0

3 years ago

Read 2 more answers

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

3 years ago

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san4es73 [151]

Shesp ends reading 219 hours reading that book

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3 years ago

What is the answer to this equation “A = ?”<br><br> G(a + h) = M

sasho [114]

Answer:

a = M -Gh/G

Step-by-step explanation:

in order to make a the subject of fomular , you will open the bracket first and then combine the like terms.

G(a + h) = M

Ga + Gh = M

Ga = M - Gh

since G is disturbing a from standing alone, we divide both sides by G

Ga/G = M- Gh/ G

a = M -Gh/G

7 0

3 years ago