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saul85 [17]
3 years ago
8

Hello please help i’ll give brainliest

Physics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

Applied force

Explanation:

She is having to purposefully move the box herself to get it to go anywhere.

worty [1.4K]3 years ago
5 0

Answer

applied force

Explanation:

If a person is pushing a desk across the room, then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person. ... For example, if a book is resting upon a surface, then the surface is exerting an upward force upon the book in order to support the weight of the book.

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In which situation can you be at rest and moving at then same time
anyanavicka [17]

If you are stationary, but in/on a moving vehicle/object you can be at rest and moving at then same time.

<u>Explanation</u>:

  • A particle, when viewed from a given frame of reference, cannot be both at rest and in motion. However, in one frame of reference, a particle can be in motion whereas in another frame of reference the particle is in motion.
  • For example, if you are seated in a plane, the plane is stationary in that reference frame and the Earth moves under it, but in the reference frame of the Earth, the plane is moving concerning the Earth. When you are standing still on Earth, in your frame of reference, the Earth is stationary, and the Sun and stars move around the Earth.
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3 years ago
A rotating object has an angular acceleration of α = 0 rad/s2. Which one or more of the following three statements is consistent
Murrr4er [49]

Answer:

A,B and C

Explanation:

Statement A  

At all times, angular velocity is \omega = 0\,{\rm{rad/s}  

Angular acceleration is the rate of change in angular velocity with respect to time.  

Angular velocity and angular acceleration are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

Which when re-arranged becomes  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

There’s no change in angular velocity anytime when the angular velocity is \omega = 0\,{\rm{rad/s}}

The equation can be modified as follows:  

\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero hence statement A is valid.  

Statement B  

Angular acceleration is the rate of change in angular velocity with respect to time.  

Angular velocity and angular acceleration are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

Which when re-arranged becomes  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

There’s no change in angular velocity anytime when the angular velocity is \omega = 10\,{\rm{rad/s}}.The final and initial velocities remain the same.  

The equation can be modified as follows:  

\begin{array}{c}\\\alpha = \frac{{10\,{\rm{rad/s}} - 10\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero and statement B is valid  

Statement C  

Angular velocity is defined as the change in the angular position with respect to time.  

Angular velocity and angular displacement are related by  

\theta = \omega t

Which can also be modified as:  

{\theta _{\rm{f}}} - {\theta _{\rm{i}}}

Note that the final position is {\theta _{\rm{f}}}and initial position is {\theta _{\rm{i}}}

Modifying the equation to find the angular velocity we obtain  

\omega = \frac{{{\theta _{\rm{f}}} - {\theta _{\rm{i}}}}}{t}

When the angular displacement has the same value at all times, the equation becomes  

\begin{array}{c}\\\omega = \frac{{{\theta _{\rm{i}}} - {\theta _{\rm{i}}}}}{t}\\\\ = 0\\\end{array}

The angular velocity becomes zero.  

Angular acceleration and angular velocity are related by  

{\omega _{\rm{f}}} = {\omega _{\rm{i}}} + \alpha t

The expression above can be rearranged as follows:  

\alpha = \frac{{{\omega _{\rm{f}}} - {\omega _{\rm{i}}}}}{t}

At all times, the angular velocity is \omega = 0\,{\rm{rad/s}} hence initial and final velocities remain the same  

We obtain  

\begin{array}{c}\\\alpha = \frac{{0\,{\rm{rad/s}} - 0\,{\rm{rad/s}}}}{t}\\\\ = 0\\\end{array}

Therefore, the angular acceleration becomes zero and statement C is valid.  

Therefore, statements A,B and C are consistent .

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