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Vesna [10]
3 years ago
8

In a generator, as the magnet spins, opposite poles of the magnet push the electrons in opposite directions. This back-and-forth

movement of electrons is called what?
A) revolutions per minute
B) direct current
C) alternating current .
In contrast, the movement of electrons in one direction in a battery circuit is called what?
A)strength of current
B)direct current
C)alternating current .
Physics
2 answers:
natulia [17]3 years ago
8 0

Answer : (C) alternating current, (B). direct current

Explanation : In a generator, as the magnet spins, opposite poles of the magnet push the electrons in opposite directions. this back - and - forth movement of electrons is called alternating current.

1. When a conductor coil moves in a magnetic field the emf induced across the conductor that means current induced in the circuit. When a conductor coil moves under magnetic poles of opposite polarity then emf gets reversed.

2. In contrast, the movement of electrons in one direction in battery circuit is called direct current. Because it flows in one direction.

Natali [406]3 years ago
6 0
C) alternating current .
<span>
B)direct current </span>
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andre [41]
The correct answer is c. The process of deposition causes rock and soil to be slowly gained. Deposition is a geological process in which soil and rocks are added to a landform.
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irakobra [83]
It’s 5 kg because the formula is m=F/a, which is 20/4, and you’ll end up with 5 kg.
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A simple harmonic oscillator consists of a block of mass 1.80 kg attached to a spring of spring constant 210 N/m. When t = 1.70
meriva

Answer:

a) 0.441 m

b) 0 m

c) 0.441 m/s

Explanation:

Simple harmonic motion equations

ω = √(k/m)

  • ω - -angular velocity
  • k - spring constant
  • m - mass

ω  = √(210/1.8)

   = 10.8 rad/s

x = A*sin(ωt)

  • x - displacement
  • A - amplitude
  • t - time

x = A*sin(ωt)

0.139  = A * sin(10.8 * 1.7)

A = 0.441 m

when t= 0

x = 0.441*sin(0)

x0 = 0 m

velocity =Aω*cos(ωt)

             = 0.441 * cos(0)

             = 0.441 m/s

6 0
3 years ago
Question 9 of 15
Alexus [3.1K]

Answer:

d

Explanation:

5 0
2 years ago
Don't understand questions 1-4!
Vilka [71]
1ª

a)
|FR| = \sqrt{ Fr_{x}^2 + Fr_{y}^2 } = \sqrt{ 2^2 + 3.1^2 } =  \sqrt{4+9.61} =  \sqrt{13,61}
|FR| = 3.689173349
\boxed{\boxed{|FR| \approx 3.7N}}

magnitude: 3.7 N
--------------------------------------------

\Theta = tg^{-1} | \frac{ Fr_{x} }{ Fr_{y} } |
\Theta = tg^{-1} ( \frac{2}{3.1} )
\Theta = 32.82854179
\boxed{\boxed{\Theta \approx 33^0anticlockwise/horizontal}}

b)

|FR| = \sqrt{ Fr_{x}^2 + Fr_{y}^2 } = \sqrt{ 16^2 + 6^2 } = \sqrt{256+36} = \sqrt{292}
|FR| = 17.08800749
\boxed{\boxed{|FR| \approx 17.1N}}

magnitude: 17.1 N
----------------------------------------------

\Theta = tg^{-1} | \frac{ Fr_{x} }{ Fr_{y} } |
\Theta = tg^{-1} ( \frac{6}{16} )
\Theta = 20.55604522
\boxed{\boxed{\Theta \approx 20.6^0anticlockwise/horizontal}} or \boxed{\boxed{\Theta \approx 21^0anticlockwise/horizontal}}

c) 

|FR| = \sqrt{ Fr_{x}^2 + Fr_{y}^2 } = \sqrt{ (3-2)^2 + 1^2 } = \sqrt{1^2+1^2} = \sqrt{2}
|FR| = 1.414213562
\boxed{\boxed{|FR| \approx 1.4N}}

magnitude: 1.4 N
----------------------------------------------
Watch the picture:
We have: 45º (isosceles) below horizontal (to 3N and 1N).
_______________________________________________
_______________________________________________

4ª

a)

Cos40^0 =  \frac{y}{350}

0.7660444431 =  \frac{y}{350}

y = 0.7660444431*350

y= 268.1155551

\boxed{\boxed{y \approx 268 N}}

--------------------------------------------------------

b)

<span>In opposite directions</span>

|FR| = \sqrt{ Fr_{x}^2 - Fr_{y}^2 } = \sqrt{ 350^2 - 268^2 } = \sqrt{122500 - 71824} = \sqrt{50676}
|FR| = 225.1133048
\boxed{\boxed{|FR| \approx 225N}}


7 0
3 years ago
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