The ordered pairs that are located 8 units away from the point (2, 1) are; (-6,1), (10,1), (2,-7) and (2,9)
<h3>Ordered pairs and Distance.</h3>
The ordered pairs which can be 8 units away from the point, (2, 1) are pairs in which case, either x or y coordinates or both are 8 units from the given pair of coordinates (2,1).
Hence, the following pair of coordinates have x or y coordinates which are 8 units away from the x or y coordinates of the given pair of coordinates.
Read more on coordinates;
brainly.com/question/3447129
Diagram A and Diagram B do not form a triangular prism
Step-by-step explanation:

![\text{Other solution}\\\\(x^2-y^2)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\= [(x-y)(x+y)]^2\\\\\text{use}\ (ab)^n=a^nb^n\\\\=(x-y)^2(x+y)^2](https://tex.z-dn.net/?f=%5Ctext%7BOther%20solution%7D%5C%5C%5C%5C%28x%5E2-y%5E2%29%5E2%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5C%5C%5C%5C%3D%20%5B%28x-y%29%28x%2By%29%5D%5E2%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%28ab%29%5En%3Da%5Enb%5En%5C%5C%5C%5C%3D%28x-y%29%5E2%28x%2By%29%5E2)
Answer: lol why would you ask a question if it is not about school homework
Step-by-step explanation:
Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.
Step-by-step explanation:
Since we have given that
Mean rate defects per unit = 0.3
Since we will use "Poisson distribution":

But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.

So,

so, it becomes,

Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.