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yan [13]
3 years ago
15

A function is represented by the set of ordered pairs shown below.

Mathematics
1 answer:
Effectus [21]3 years ago
6 0
Answer: {3, 5, 7}

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The range is the set of outputs of a relation or function. In other words, it's the set of possible y values. Recall that ordered pairs are of the form (x,y) so the y coordinate is listed after the x. The output is listed after the input. The output values are y = 3, y = 3, y = 3, y = 5, y = 7. So we simply list these outputs without the "y=" portion. Toss out any duplicates. Only write the unique output values. 

The curly braces surrounding the list of values tells us that we have a set. 
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Verdich [7]

a. 3 × 10^0

b. 33. 6 × 10^0

c. 57. 6 × 10^2

d. 4. 0 × 10^-7

e. 7. 0 × 10^-1

<h3>What is scientific notation?</h3>

Scientific notation is simply a way of expressing numbers that are too large or small to be written in decimal form.

It may be referred to as standard index form or scientific form.

From the information given, we have;

a. 0. 000003 is written in standard form as;

= 3 × 10^-6 × 3 × 10^6

= 3 × 10^-6 + 3

= 3 × 10^0

= 3

b. 56, 000, 000. 00 is written in standard form as;

= 5. 6 × 10^7 × 6 × 10^-7

= 33. 6 × 10^7 -7

= 33. 6 × 10^0

= 33. 6

c. 8. 0 × 10^-3 × 7. 2 × 10^5

= 57. 6 × 10^-3 + 5

= 57. 6 × 10^2

d. 4. 0 × 10^-3 × 4. 0 × 10^-4

= 4. 0 ^ -3 +(-4)

= 4. 0 × 10^-7

e. 7. 0 × 10^3 × 7. 0 × 10^4

= 7. 0 × 10^ 3-4

= 7. 0 × 10^-1

Thus, scientific notation is also referred to as standard form.

Learn more about scientific notation here:

brainly.com/question/27862246

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Step-by-step explanation:

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10m-2/5=9.6 (where 9 and 3/5 is equal to 9.6)

50m-2=48 (i multiplied 10m by 5 and 9.6 by 5)

50m=50 ( i added 2 to both sides)

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Sasha performs an experiment. She chooses one marble from each of three sacks. The first sack has black (B) and white (W) marble
Paladinen [302]

Answer:

Option D is correct

Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

The tree diagram

The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

<em>The only tree diagram that illustrates this is: option D</em>

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