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Ganezh [65]
3 years ago
7

Colton has n nickels and d dimes. He has no more

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

(`n*0.05)+(d*0.10)<2

Step-by-step explanation:

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3/4 x 2/3 as a fraction
svet-max [94.6K]

Answer:

Hi, There!

Your Answer is \frac{6}{12} ~or~\frac{1}{2}

Step-by-step explanation:

\frac{3}{4} ~x~\frac{2}{3} = \frac{3 ~x~2}{4~x~3}

Which Equals

\frac{6}{12}

Now if you dived the numerator and denominator by 6 you Get...

\frac{1}{2}

Therefore, I hope this helps!

Take Care!

-Jay-

5 0
3 years ago
What does each equation have in common
Leona [35]

The equations have operations, variable, an equal sign in common.

<h3>What is an Equation?</h3>

An equation is a mathematical expression that contains an equals symbol.

As per the definition, the equation contain operations, variable, an equal sign. That means whatever be the equation then it must contain operations, variable, an equal sign.

So, all the equations have operations, variable, an equal sign these three things in common.

For example: 4a+b=0

Learn more about equation here:

brainly.com/question/10413253

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4 0
2 years ago
Find the radius of the sphere with a volume of 32/81π cubic yards. Write your answer as a fraction in simplest form.
alexdok [17]

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=\frac{32\pi }{81} \end{cases}\implies \cfrac{32\pi }{81}=\cfrac{4\pi r^3}{3}\implies \cfrac{96\pi }{81}=4\pi r^3 \\\\\\ \cfrac{96\pi }{324\pi }=r^3\implies \cfrac{8}{27}=r^3\implies \sqrt[3]{\cfrac{8}{27}}=r\implies \cfrac{\sqrt[3]{8}}{\sqrt[3]{27}}=r\implies \cfrac{2}{3}=r

5 0
4 years ago
Fred had 264 books in his personal library he donated 2/11 of these books to the public library how many books did you donate
Citrus2011 [14]
Fred donated 48 books.
8 0
3 years ago
Read 2 more answers
Bev has to cut her grandma's grass this weekend and wants to know exactly how much area she will be cutting. Calculate the area
never [62]
29+15+19=63-(4+25)=34 i think
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3 years ago
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