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Elden [556K]
2 years ago
14

Does Pres. Trump have the” honesty and trustworthy you expect in a president?”. Poll surveyed 1015 adults and 34% of them (clear

ly less than half), answered yes. Could Trump’s adversaries conclude from this that only a minority (less than half) of the population of Americans thought Trump had the honesty and trustworthy to be president? Carry out an appropriate test at the 0.10 significance level. Use the five-step framework to organize your work
Mathematics
2 answers:
Galina-37 [17]2 years ago
7 0

Answer:

trump is trustworthy and he is honest  so yes he is what we need

Step-by-step explanation:

aliina [53]2 years ago
3 0

Answer:

is this an actual assignment or do u just want our opinion

Step-by-step explanation:

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
1 3/5(t-6)=-0.4 solve the equation​
andrew11 [14]

t= 6 1/4 hope this helps

6 0
3 years ago
If you have 63 books and you donate 1/3 of you’re books how many will you have left
ryzh [129]

Answer: 42

Step-by-step explanation: you would do 63 divided by 3 then you would get 21 and do 21×2 and get 42

6 0
3 years ago
How many solutions exist for the system of equations graphed below?
Zinaida [17]

Answer:

one

Step-by-step explanation:

When a system of equations is graphed, the solution is the coordinate that is plotted at the intersection of the two lines.

If the two lines cross once, there is only one solution.

If the two lines are on top of each other then there are infinitely many solutions.

If the two lines are parallel ( and never touch ) then there are no solutions

By looking at the graph we notice the two lines intersect once. So we can conclude that there is only one solution.

6 0
1 year ago
Read 2 more answers
Write two expressions that have a GCF of 8xy
Svetllana [295]
32x^2y
8xy^6
the gcf is 8xy
6 0
2 years ago
Read 2 more answers
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