The Genotype of the father is gg; The possible genotypes of offspring will be
Gg; gg; Gg; gg. Therefore there is a 50% chance that the child will have galactosemia. The parents could have had; both had gg genotype,or both had Gg genotype, or one had gg and the other Gg.
The shoreline is one of the harshest and most changeable environments for living creatures. The changing tides shift the environment dramatically within a sub-daily cycle. Here, we can consider two typical shoreline organisms, and the changing environment they must endure. Within the rocky shore environment, an octopus would be within the shallow but open sea environment during high tide, and water temperature and salinity conditions would be fairly constant. During low tide, the octopus might become trapped in a rock pool. This environment is dramatically different. The water temperature and salinity might increase drastically with exposure to solar radiation. The octopus is also more vulnerable to predation by humans and other land animals. Within the sandy shore environment, sand clams would be actively positioned at the interface of the sand and water, and will be actively filtering sea water for detritus. During low tide, the sand would be exposed to the air, and the clams would burrow down into the sand so as to avoid dessication.
They probably chose this over black since black absorbs he most heat, and if something like a power outage occurs during the hot summer, ya want to stay as cool as possible...this is just my idea.
<span>upward rotation, abduction</span>
The percentage of the white salamander population is 16%.
<h3>Hardy-Weinberg Equilibrium Equation</h3>
The genotypic frequencies within a population can be expressed by the binomial (p + q)² = 1, which can be developed and represented by the following equation:
p = frequency of the dominant allele;
q = frequency of the recessive allele;
p² = frequency of the zygous dominant genotype;
2pq = frequency of the heterozygous genotype;
q² = frequency of the zygous recessive genotype.
Also according to the equation presented (p² + 2pq + q² = 1), we will have the following distribution of genotypes:
- CC = 0.36 = 36%
- Cc = 0.48 = 48%
- cc = 0.16 = 16%
Learn more about recessive allele in brainly.com/question/844145
