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2 answers:
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<h3>The probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.</h3>
Step-by-step explanation:
Here, the total sample of people has total 535 people.
The percentage of people liking chocolate chip cookies = 65%
Now, 65% of 535 =
⇒ 348 people in total like chocolate chip cookies.
⇒ n(C) = 348
The percentage of people liking peanut butter chip cookies = 37%
Now, 37% of 535 =
⇒ 198 people in total like peanut butter chip cookies.
⇒ n(B) = 198
Percentage of people liking both chocolate &peanut butter chips = 25%
Now, 25% of 535 =
⇒ 134 people in total like both chocolate &peanut butter chips
⇒ n(C ∩ B ) = 134
Now, n( C U B) = N(C) + n(B) - n(C ∩ B )
= 348 + 198 - 134 = 412
P( person likes cookies with chocolate or peanut butter chips)
=
Hence, the probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.
Answer:
Step-by-step explanation:
The first question is asking you how many visitors there were, using the function model provided, when x = 0. Filling that in gives you:
Anything to the 0 power = 1, so
y = 18,582(1) and
y = 18,582
The second question is asking you how many visitors there were on the 9th weekend, when x = 9:
and
so
y = 7199
The last question is asking on what weekend (unknown x) are there
y = 15.051 visitors. That requires using a log to solve for x. Set it up first:
Start by dividing both sides by 18,582 to get:
Now we need to take the log of both sides to get that x out from its exponential position. By taking the log of the right side, we are given the ability to bring the x down in front:
log(.8099773975) = x log(.90)
Now divide both sides by log(.90) to get
x = 2.000
That means that on the second weekend, there were approximately 15,051 visitors.