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Gekata [30.6K]
3 years ago
6

Line 1 passes through the points (9,-4) and (3, 2)

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer:

y = -1x + 4

Step-by-step explanation:

equation for one is y = -1x + 5 simple going back from point (5,-2) gave me a b of 4 so yess

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Show why x−3 is a factor of m(x)=x3−x2−5x−3. Justify your answer. You can show this using remainder theorem, long division, synt
Marat540 [252]

The factors of a polynomial function are the zeros of the function

It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3

<h3>How to show why the x - 3 is a factor</h3>

The function is given as:

m(x) = x^3 - x^2 - 5x - 3

The factor is given as:

x - 3

Set the factor to 0

x - 3 = 0

Solve for x

x = 3

Substitute 3 for x in the function

m(3) = 3^3 - 3^2 - 5(3) - 3

Evaluate

m(3) =0

Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3

Read more about factors at:

brainly.com/question/11579257

7 0
2 years ago
What is the slop for 3x + y = 1
Margarita [4]

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Step-by-step explanation:

5 0
3 years ago
Rephrase in contrapositive form:
miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. \sim q \rightarrow \sim p

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.

Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"

The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

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2 years ago
PLEASE HELP!!!
Scilla [17]
You need the Law of Cosines here and you use it when you have 2 sides and an enclosed angle.  The side across from the angle is the one we are looking for.  The correct way to express the Law using what we have is the last choice above.  Side RT is the unknown, and it is across from the angle that is enclosed between the 2 other sides.
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3 years ago
Please, Need Help ASAP!!
Jobisdone [24]

Answer:

I think it's A I'm not sure

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2 years ago
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