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3 years ago

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HELP PLEASE! Identify the distance between the points (2,4,12) and (7,4,0), and identify the midpoint of the segment for which t

hese are the endpoints. Round to the nearest tenth, if necessary.

1 answer:

hjlf3 years ago

5 0

Do u have a paper to show the model Of your question..

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The minimum level of inventory needed to meet customer demand is called the

Licemer1 [7]

Answer:

minimum level of stock

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3 years ago

Given that ABCD is a rhombus, find the value of x.<br> (X+14)

Kay [80]

Answer:

option B. $x=38^o$

Step-by-step explanation:

we know that

1) The two diagonals of a rhombus are perpendicular

2) The sum of the interior angles in any triangle must be equal to 180 degrees

Let

O ----> the intersection point of the diagonals of the rhombus

In the right triangle OAD

$x^o+(x+14)^o+90^o=180^o$

solve for x

$x^o+(x+14)^o=90^o$

$2x=90^o-14^o$

$2x=76^o$

$x=38^o$

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3 years ago

Consider the data shown on the graph. The y-intercept represents a starting salary of 5 32.500 for a new employee. The slope rep

sasho [114]

Answer:

300

Step-by-step explanation:

6 0

3 years ago

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Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v

disa [49]

Answer:

Option A $V_B=19\ cm^3$

Step-by-step explanation:

The volume of a cone is:

$V_B = \pi\frac{hr ^ 2}{3}$

The volume of a cylinder is:

$V_A = \pi(r ^ 2)h$

Both figures have the same height h and the same radius r.

The volume of the cylinder $V_A = 18\pi\ cm ^ 3$

We want to find the volume of the cone.

Then, we find r and h:

$V_A = 18\pi = \pi(r ^ 2)h$

We simplify.

$V_A = 18 = (r ^ 2)h$

Then the product of $(r ^ 2)h = 18$ .

We substitute this in the cone formula and get:

$V_B =\frac{\pi}{3}(18)\\\\V_B = \frac{18}{3}\pi\\\\V_B=19\ cm^3$

8 0

3 years ago

Read 2 more answers

over the weekend, Brady and Jake drove to Key West go scuba diving. Now they're preparing to go home.Brady needs gas for his jee

velikii [3]

His car gets 21 mpg (miles per gallon). With 1 gallon he can drive 21 miles. For example, with 10 gallons, he can drive 21 mpg * 10 gal = 210 miles.

He bought $19.50 worth of gas at $1.40 per gallon.
$19.50 / ($1.40/gal) = 13.93 gal

He already had 5 gal of gas in his tanks, so now he has
5 gal + 13.93 gal = 18.93 gal

With 18.93 gal, he can drive
18.93 gal * 21 mpg = 292.5 miles

3 0

3 years ago