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Vera_Pavlovna [14]

3 years ago

7

A couch and coffee table cost a total of $1272. The cost of the couch is two times the cost of the coffee table. Find the cost o

f each item.

2 answers:

Lunna [17]3 years ago

5 0

Answer:

318+954

Step-by-step explanation:

divide 1272 by 2 to get what they would cost if they were the same amount then divide that by 2 to get 318 times that by 3 to get 954 and add 318 to get 1272

frez [133]3 years ago

5 0

The couch would be $848 and the coffee table is $424.

Since the couch cost twice as much as the coffee table you would take 1272 and divide it by 3. Making it $424. If you multiply 424 by 2 it gives you $848 and adding the $424 will give you $1272. The other answer is wrong. You don’t divide by two.

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Answer:

Colin will have £4,836.92 in his account after 3 years

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

Find the sum of the three expressions and choose the correct answer. -8a 3 b + 3a2 b 2 - 5 2 + 5a 2 b 2 3a 3 b + 7 - 9a 2 b 2

Damm [24]

Answer:

-9ab3a3b-52

Step-by-step explanation:

-8a3b+3a2b2-52+5a2b3a3b+7-9a2b2

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-14a3b-52+5a2b3a3b

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3 0

3 years ago

Thanks for helping with calculus

allochka39001 [22]

Integrating $f(x)$ gives

$g(x)=\displaystyle\int f(x)\,\mathrm dx=C+\sum_{n=0}^\infty\frac{a_n}{n+1}x^{n+1}$

Notice that $x=0$ forces all terms in the sum to be 0, so that

$g(0)=C=5$

and hence

$g(x)=\displaystyle5+\sum_{n=0}^\infty\frac{a_n}{n+1}x^{n+1}$

making the first option correct.

3 0

4 years ago

41. Assuming that a man can complete the work alone in x days, his work in four days would be: a) b) X X C d) 4x x 42. If a man

Schach [20]

Percentage and ratio word problems require understanding of the relationship between variables from which the question is formed

The options that give the correct values of the duration of the work are;

$41. \ c) \ \dfrac{4}{x}$

$42. \ d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. a) 35 days

44. c) 21·a + 28·b = 1

45. c) (42, 56)

Reasons:

41. Number of days it takes a man to complete the work alone = x days

Therefore;

$The \ work \ done \ by \ the \ man \ in \ one \ day = \dfrac{1}{x}$

$The \ work \ done \ in \ four \ days \ by\ the \ man = 4 \times \dfrac{1}{x} = \dfrac{4}{x}$

The correct option is $c) \ \dfrac{4}{x}$

42. Number of days it takes a man to complete the work alone = x days

$Work \ done \ by \ a\ man \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ four \ men \ in \ one \ day = \dfrac{4}{x}$

Number of days it takes a boy to complete the work alone = y days

$Work \ done \ by \ a \ boy \ in \ one \ day = \dfrac{1}{x}$

$Work \ done \ by \ six \ boys \ in \ one \ day = \dfrac{6}{y}$

4 men and 6 boys work for 5 days to complete the work

Therefore, work done by 4 men and 6 boys in 1 day is therefore;

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

The correct option is therefore;

$d) \ \dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

43. As per the case study, we have;

Case 1

$\dfrac{4}{x} + \dfrac{6}{y} = \dfrac{1}{5}$

Which gives;

$\dfrac{6\cdot x + 4\cdot y}{y \cdot x} = \dfrac{1}{5}$

30·x + 20·y = y·x

Case 2

$\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$

Which gives;

$\dfrac{4\cdot x + 3\cdot y}{y \cdot x} = \dfrac{1}{7}$

28·x + 21·y = y·x

Therefore;

30·x + 20·y = 28·x + 21·y

∴ 2·x = y

Plugging in the value of <em>y</em> = 2·x, in Case 1 gives;

$\dfrac{4}{x} + \dfrac{6}{2 \cdot x} = \dfrac{1}{5}$

$\dfrac{2 \times 4 + 6}{2 \times x} = \dfrac{14}{2 \times x} =\dfrac{7}{x} = \dfrac{1}{5}$

7 × 5 = x

x = 7 × 5 = 35

The number of days, <em>x</em>, it takes a man to complete the work alone, is given by option; a) <u>35 days</u>

44. For the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , if $a = \dfrac{1}{x}$ , and $b = \dfrac{1}{y}$ , we have;

$3 \cdot a+ 4\cdot y = \dfrac{1}{7}$

21·a + 28·y = 1

The correct option is option C. <u>21·a + 28·b = 1</u>

45. A solution to the equation $\dfrac{3}{x} + \dfrac{4}{y} = \dfrac{1}{7}$ , is given by the values of <em>x</em>, and <em>y</em>, that gives;

$\dfrac{1}{14} + \dfrac{1}{14} = \dfrac{1}{7}$

We have;

3 × 14 = 42

4 × 14 = 56

Therefore, a solution to the equation is (42, 56)

The correct option is $c) \ \underline{ (42, \ 56)}$

Learn more here:

brainly.com/question/11825953

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3 0

2 years ago

The simple interest on a certain sum of money for 2(1/2) years at 12% per annum is Rs.40

shepuryov [24]

Step-by-step explanation:

$si = p \times \frac{r}{100} \times t$

$si = 40 \times \frac{12}{100} \times \frac{5}{2}$

$si = \frac{40 \times 12 \times 5}{100 \times 2}$

$si = \frac{4 \times 12 \times 5}{10 \times 2}$

$si = \frac{4 \times 12 }{5\times 2}$

$si = \frac{2 \times 12}{5}$

$si = \frac{24}{5}$

$si = 4.8$

3 0

3 years ago