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Andrew [12]
3 years ago
14

Triangle ABC is similar to triangle PQR. List all of the proportions that can be used to find n?

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0

Answer:

its smaller and its upside down

Step-by-step explanation:

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What is the rule for Aaliyah’s machine? Try to write the rule as an equation.
Eva8 [605]

Answer:

  f(x) = 2x +1

Step-by-step explanation:

Apparently the ordered pairs are ...

  (x, f(x)) = (1, 3), (2, 5), (3, 7), (4, 9)

We note that as x increases by 1, the value of f(x) increases by 2. The difference between f(x) and 2x is 3-2·1 = 1, so we have ...

  f(x) -2x = 1

  f(x) = 2x +1 . . . . . . add 2x

4 0
3 years ago
Please help me !! I need help ASAP
vlada-n [284]

Answer:

1/5

Step-by-step explanation:

3 0
3 years ago
Simplify the expression:<br> 2(3n+4)-2(2n+5)
inessss [21]
First use distributive property:
2(3n + 4) - 2(2n + 5)
6n + 8 - 4n - 10
Group like terms:
6n - 4n + 8 - 10
Add like terms:
2n - 2
4 0
2 years ago
Read 2 more answers
You have $60 and your sister has 120 you are saving $14 per week and your sister is saving $10 per week how long will it be befo
hodyreva [135]

Answer:

15 weeks and you both will have $270

Explanation:

60+14x=120+10x

4x=60

x=15 weeks

amount= 60+14*15= $270

5 0
2 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
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