A 7.5 kg block is placed on a table. If its bottom surface area is 0.6 m2, how much pressure does the block exert on the tableto
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Answer:
The area of tarpaulin is 1315.63 ft^2.
Step-by-step explanation:
height, h = 20 feet
circumference, C = 102 feet
Let the radius is r.
Circumference, C = 2 x 3.14 x r = 102
r = 16.24 feet
Let the slant height is L.
The curved surface area is
S = 3.14 x r x L
S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2
We know that a triangle is 180 degrees.
x=39