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adoni [48]
3 years ago
14

Consider the recursively defined function below

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

So, the first five terms of the sequence defined by the given recursive function are shown below.

F(1) 0.75 f(2) 1.1 F(3) 1.45 F(4) 1.8 f(5) 2.15

written on plato

Step-by-step explanation:

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Need help with a simple problem 2^x=3^x+1
KiRa [710]
For x\ \textgreater \ 0, 2^x\ \textless \ 3^x, all the more 2^x\ \textless \ 3^x+1, therefore no solution.

For x=0, we have 2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2. Obviously that' false.

For x\ \textless \ 0 both 2^x and 3^x, where 2^x\ \textgreater \ 3^x, belong to the range (0,1), then 3^x+1 belong to the range (1,2).
Those ranges don't have a common part, therefore, again, no solution.

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4 0
3 years ago
Decrease £101 by 43%
Burka [1]


101 - Percentage decrease =

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101 - 43% × 101 =

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3 years ago
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I rly need help on this ty
REY [17]

Answer:

Oh I didn’t know that lol

Step-by-step explanation:

Lol

4 0
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DedPeter [7]

Answer:

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