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olga_2 [115]
2 years ago
7

The photography club has 36 memebers, 16 girls and 20 boys. what is the ratio of girls to boys in the photography club?

Mathematics
2 answers:
exis [7]2 years ago
8 0

Answer:

4:5

girls:boys

16:20

divide both by 4

4:5

sdas [7]2 years ago
8 0
Answer: B) 4:5

Step-by-Step Solution:

Total No. Of Members = 36
No. Of Girls = 16
No. Of Boys = 20

Ratio of Girls to Boys
= 16/20
= 8/10
= 4/5
=> 4:5

Correct Option is C) 4:5
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Answer:

Step-by-step explanation:

V=πr2h

3

r Radius

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3 years ago
i dont understand equations of parallel and perpendicular lines here's one of my teachers examples y=2x+4 (-2,1)
SIZIF [17.4K]
Parallel lines will never touch each other while perpendicular forms like an X shape. The slope for the parallel is the same while the perpendicular is a negative reciprocal. (Ex for negative reciprocal. 2/4=4/2)
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3 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)

400=81+169-234(cosA)   150=-234(cosA)

cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
I am not sure if this is right can someone check it ASAP please
NikAS [45]

Answer:

x=10

Step-by-step explanation:

3(4x-12) = 84

Divide each side by 3

3/3(4x-12) = 84/3

4x-12 =28

Add 12 to each side

4x-12+12 = 28+12

4x= 40

Divide each side by 4

4x/4 = 40/4

x = 10

6 0
3 years ago
What is the m∠N ? Can someone help me :)
Sauron [17]

Answer:

<h2>61°</h2>

Step-by-step explanation:

Use the sine law:

\dfrac{MO}{\sin(\angle N)}=\dfrac{NM}{\sin(\angle O)}

We have:

MO=18\\\\NM=6\\\\m\angle O=17^o\to\sin17^o\approx0.2924

Substitute:

\dfrac{18}{\sin(\angle N)}=\dfrac{6}{0.2924}         <em>cross multiply</em>

6\sin(\angle N)=(18)(0.2924)

6\sin(\angle N)=5.2632          <em>divide both sides by 6</em>

\sin(\angle N)=0.8772\to m\angle N\approx61^o

4 0
3 years ago
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