Find the volume of this cone.
1 answer:
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F(x)= 0.02x^2 + 0.08x + 30.6
so for f(0) all that means is where you see x plug 0 for x..
f(0)= 0.02(0)^2+ 0.08(0) + 30.6
f(0)= 30.6
f(4)= 0.02(4)^2 + 0.08(4) + 30.6
f(10)= 0.02(10)^2 + 0.08(10) + 30.6
attached are calculated answers
so for f(0) all that means is where you see x plug 0 for x..
f(0)= 0.02(0)^2+ 0.08(0) + 30.6
f(0)= 30.6
f(4)= 0.02(4)^2 + 0.08(4) + 30.6
f(10)= 0.02(10)^2 + 0.08(10) + 30.6
attached are calculated answers