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den301095 [7]
3 years ago
10

Order the following from least to greatest 0.222, 1/5, 0.02

Mathematics
2 answers:
frutty [35]3 years ago
7 0
.222, 1/5, .02
Write them in decimal form
.222, .20, .02
Look at the tenths place, since the third one has a zero which is less than 2 so .02 would go first.

Then look at the first two, since the tenth place is the same, we look at the hundredths place since 0 is less than 2, .2 goes before .222. 
 
The order would be
.02, 1/5, .222
lorasvet [3.4K]3 years ago
6 0
1. Put all values in decimals

0.222=0.222

1/5= 0.2

0.02= 0.02

2. Order the cakes from least to greatest

0.02, 0.2, 0.222


Hope this helps!
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Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?
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The equation of the elipse is given by:

\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1

The equation of an elipse of center (x_0, y_0) is given by:

\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

x_0 = \frac{27 + 1}{2} = 14

y_0 = \frac{0 + 0}{2} = 0

a = \frac{27 - 1}{2} = 13

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It has eccentricity of \frac{5}{13}, thus:

\frac{5}{13} = \frac{c}{a}

\frac{5}{13} = \frac{c}{13}

c = 13

Thus, b is given according to the following equation:

c^2 = a^2 - b^2

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b = \sqrt{144}

b = 12

The equation of the elipse is:

\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1

A similar problem is given at brainly.com/question/21405803

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