Answer:
The answer is 120 feet.
Step-by-step explanation:
The area of the field (A) is:
A = w · l (w - width, l - length)
It is known:
A = 12,000 ft²
l = w - 20
So, let's replace this in the formula for the area of the field:
12,000 = w · (w - 20)
12,000 = w² - 20
⇒ w² - 20w - 12,000 = 0
This is quadratic equation. Based on the quadratic formula:
ax² + bx + c = 0 ⇒
In the equation w² - 20w - 12,000 = 0, a = 1, b = -20, c = -12000
Thus:
So, width w can be either
or
Since, the width cannot be a negative number, the width of the field is 120 feet.
Answer:
Step-by-step explanation:
Remark
The angle formed by the intersection of a tangent to a circle and an intersecting secant is 1/2 (Arc PS - arc PR)
PS = 208
PR = 74
Solution
x = 1/2 (208 - 74)
x = 1/2 (134)
x = 67
Answer:
<h2>
y = 6x - 1</h2>
Step-by-step explanation:

(0, -1) ⇒ x₁ = 0, y₁ = -1
(1, 5) ⇒ x₂ = 1, y₂ = 5
So the slope:

The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.
(0, -1) ⇒ x₀ = 0, y₀ = -1 ⇒ b = -1
Therefore:
y = 6x - 1 ← the slope-intercept form of the equation
Answer: B. 9
Step-by-step explanation:
First, find the median of the data set. This set has an even number of points, so find the average between the two middle points: 18 and 19. 18+19 = 37. 37/2 = 18.5. <em>The median is 18.5.</em>
Now, to find the lower quartile, find the median of the lower half of the data set {11, 12, 14, 15, 18}. The number in the middle is 14. <em>The lower quartile is 14.</em>
To find the upper quartile, find the median of the upper half of the data set {19, 21, 23, 25, 55}. The number in the middle is 23. <em>The upper quartile is 23.</em>
To find the interquartile range, subtract the lower quartile from the upper quartile. 23-14 = 9. <em>The interquartile range is 9.</em>
Answer:
1 pm
Step-by-step explanation:
We have to find their LCM, or least common multiple
Multiples of 36: 36, 72, 108, 144, 180, 216, ......
Multiples of 45: 45, 90, 135, 180, ....
180 mins is their LCM.
180 mins = 3 hours
10am + 3hours = 1 pm
-Chetan K