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stealth61 [152]
3 years ago
9

(b) The perimeter of a rectangular painting is 250 cm.

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
53x2=106
250-106= 144
144/2=72
The length is 72cm
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Find the value of x in the equation. 6x+48=60
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Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn
Vinil7 [7]

Answer:

t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n

Step-by-step explanation:

Arithmetic sequence:

       \sf \boxed{t_n=a+(n-1)d}

Here a is the first term and d is the common difference.

      t_{14}= 6    ⇒  \sf a + 13 d = 46  ------------(I)

     \sf t_{20} = 100 ⇒   a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1)    a + 19d = 100

(II)    a + 13d   =  46

      <u>-    -            -</u>

               6d = 54

                d = 54 ÷ 6

                 \sf \boxed{d = 9}

Substitute d = 9 in equation(I) and find 'a',

    a + 13*9= 46

     a + 117  = 46

              a = 46 - 117

              a = -71

         

\sf t_3 = -71 + 2*9

   = -71 + 18

   = -53

          \sf t_7 = -71 + 6*9

              = -71 + 54

              = -17

\sf t_n= -71 + (n-1)*9

    = -71 + 9*n - 1 *9

    = -71 + 9n - 9

    = -71 - 9 + 9n

     = - 80 + 9n

   

   

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1 year ago
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5 0
3 years ago
A grading scale is set up for 1000 students' test scores. It assumes the
astra-53 [7]

Answer:

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

It assumes the scores are normally distributed with a mean score of 75 and a standard deviation of 15.

This means that \mu = 75, \sigma = 15

How many students will score between 48 and 75?

First we find the proportion, which is the pvalue of Z when X = 75 subtracted by the pvalue of Z when X = 48. So

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 75}{15}

Z = 0

Z = 0 has a p-value of 0.5

X = 48

Z = \frac{X - \mu}{\sigma}

Z = \frac{48 - 75}{15}

Z = -1.8

Z = -1.8 has a p-value of 0.0359

1 - 0.0359 = 0.4641

Out of 1000:

0.4641*1000 = 464

464 students will score between 48 and 75. Using the z-distribution, we measure how many standard deviations each score is from the mean, then find the p-value associated with each score to find the proportion, and from the proportion, we find how many out of 1000.

7 0
3 years ago
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