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Artemon [7]
3 years ago
5

The p53 gene is important to the cell cycle in G1 and G2, and cancer. What happens to the cell cycle when a mutation occurs in t

he p53 gene?
(please no links!!)
Biology
1 answer:
german3 years ago
5 0

Answer:

PFFT this might help? sorry if not mate

Explanation:

Cell cycle checkpoint controls play a major role in preventing the development of cancer [see Sherr, 1994, for a more detailed discussion]. Major checkpoints occur at the G1 to S phase transition and at the G2 to M phase transitions. Cancer is a genetic disease that arises from defects in growth-promoting oncogenes and growth-suppressing tumor suppressor genes. The p53 tumor suppressor protein plays a role in both the G1/S phase and G2/M phase checkpoints. The mechanism for this activity at the G1/S phase checkpoint is well understood, but its mechanism of action at the G2/M phase checkpoint remains to be elucidated. The p53 protein is thought to prevent chromosomal replication specifically during the cell cycle if DNA damage is present. In addition, p53 can induce a type of programmed cell death, or apoptosis, under certain circumstances. The general goal of p53 appears to be the prevention of cell propagation if mutations are present. The p53 protein acts as a transcription factor by binding to certain specific genes and regulating their expression. One of these, WAF1 or Cip1, is activated by p53 and is an essential downstream mediator of p53-dependent G1/S phase checkpoint control. The function of p53 can be suppressed by another gene, MDM2, which is overexpressed in certain tumorigenic mouse cells and binds to p53 protein, thus inhibiting its transcriptional activation function. Other cellular proteins have been found to bind to p53, but the significance of the associations is not completely understood in all cases. The large number of human cancers in which the p53 gene is altered makes this gene a good candidate for cancer screening approaches.

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Transcribe the following DNA strand into mRNA and translate that strand into a polypeptide
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7 0
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Read 2 more answers
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8 0
2 years ago
You measure the absorbency of a 0.5 ml solution and you find that it is 1.2. You then dilute this solution by adding 0.5 ml of p
Vsevolod [243]

Answer:

The absorbency will be 0.6 (letter C)

Explanation:

A process that decreases the amount of a solute in a solution is called dilution. Dilutions are made by adding more solvent to the solution (the universal solvent is water).  

In this case, we have a 0.5 ml of a solution with a specific concentration that the absorbency is 1.2. We dilute this solution adding 0.5 ml of water (the same amount of our solution or initial volume). Then we have the double (1 mL) of the initial volume (0.5 ml), this means that the concentration will be the half (0.6) of our initial concentration (1.2).

In mathematical terms, we can use the next formula :

                                                   (C1)(V1) = (C2)(V2)

Where:

C1: initial concentration

V1: initial volume

C2: final concentration

V2:  final volume

We now that:

C1: 1.2

V1: 0.5 ml

C2: ?

V2: 1 ml

Using the formula, we have:

                                        (1.2)(0.5 ml)=(C2)(1 ml)

As the 1 ml is multiplying, pass to the other side dividing

C2= (1.2)(0.5 ml) /(1 ml)

C2=  0.6 /1

C2 : 0.6

6 0
3 years ago
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