Answer:
Ni + Sn^2+ —> Sn + Ni^2+
Explanation:
First let us generate an elemental equation for the reaction. This is illustrated below:
Ni + Sn(NO3)2 —> Sn + Ni(NO3)2
From the equation above, a solid metal Sn is formed.
Now we can generate a net ionic equation as follows:
Ni + Sn^2+ —> Sn + Ni^2+
The Best Answer: 1 - (.47+.23) = 0.30
If Ne has a mole fraction of 0.47 (or 47/100) and Ar is 0.23, then H2(or He) has a mole fraction of 0.30
This means the gas mixture is 30/100 H2(or He).
7.85 x 0.30 = 2.355 atm
For the purpose we will here use t<span>he ideal gas law:
p</span>×V=n×R×<span>T
V= </span><span>5.0 L
T= </span><span>373K
p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:
n=p×V/R×T
n= 203 x 5 / 8.314 x 373 = 0.33 mole
Answer:
Final concentration of NaOH = 0.75 M
Explanation:
For 
:-
Given mass = 90.0 g
Molar mass of NaOH = 39.997 g/mol
The formula for the calculation of moles is shown below:
Thus,
Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.
The expression for the molarity, according to its definition is shown below as:
Where, Volume must be in Liter.
It is denoted by M.
Given, Volume = 3.00 L
So,
<u>Final concentration of NaOH = 0.75 M</u>
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