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Radda [10]
4 years ago
15

In a sample of solid ba(no3)2 the ratio of barium ions to nitrate ions is

Chemistry
1 answer:
Nata [24]4 years ago
7 0
I believe the ratio is 1:2
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A 58.5 g sample of glass is put into a calorimeter (see sketch at right) that contains 250.0 g of water. The glass sample starts
Ket [755]

Answer:

The specific heat capacity of glass is 0.70J/g°C

Explanation:

Heat lost by glass = heat gained by water

Heat lost by glass = mass × specific heat capacity (c) × (final temperature - initial temperature) = 58.5×c×(91.2 - 21.7) = 4065.75c

Heat gained by water = mass × specific heat capacity × (final temperature - initial temperature) = 250×4.2×(21.7 - 19) = 2835

4065.75c = 2835

c = 2835/4065.75 = 0.70J/g°C

5 0
3 years ago
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The atomic number of polassium and
never [62]

Explanation:

Atomic radius decreases from left to right in a period.

Therefore Calcium would have a smaller atomic size.

6 0
3 years ago
Pls help! I'll give u 10 points and the brainlest answer!!!​
alekssr [168]

Answer:

371km

Explanation:

the lower the more fuel there is

7 0
3 years ago
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How is the law of conservation of matter represented in a chemical reaction?
blondinia [14]

Answer:

By balancing the chemical equation  

Explanation:

The Law of Conservation of Matter states that matter cannot be destroyed nor created.

That is, you must have the same amount of matter before and after a reaction.

Atoms are made of matter, so you must have the same number of each type of atom in the reactants as in the products. You must balance the equation.

Consider the reaction

2H₂ + O₂ ⟶ 2H₂O

You must have 2s in front of H₂ and H₂O to balance the atoms.

They give you four atoms of H and two atoms of O on each side of the arrow.

5 0
3 years ago
What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?
FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0
2 years ago
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