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Ivan
3 years ago
14

Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4

Chemistry
1 answer:
Helga [31]3 years ago
3 0

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

  • 61µg/106
  • 0.000061/106
  • 5.75×10^{-7}
  • 57.5µmol

Moles of Al3+=57.5µmol

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A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r
mojhsa [17]

To be equal as K_p , K_c needs to be divided by (RT)^{\Delta n}

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where n_{products} < n_{reactants},

then = K_p < K_c

It's because \Delta n is negative, which places (RT) in the denominator. This is how the equation will now appear.

K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}

Here you can observe the value of K_c  is greater than K_p. To be equal as K_p , K_c needs to be divided by (RT)^{\Delta n}

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about equilibrium

brainly.com/question/11336012

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6 0
2 years ago
Sort these six events from the earliest to the most recent. Democritus proposes the existence of atoms- Dalton's atomic theory-
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These events are actually sorted right, according to the time they occurred.
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4 0
3 years ago
An unknown gas contains 5.4 moles in 34 mL. If the amount of gas increases to 6.2 moles, what is the new volume?
Murljashka [212]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

  • Initial amount of gas n₁ = 5.4moles
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  • Final amount of gas n₁ = 6.2moles
  • Final volume v₂ = ?

We substitute our values into the expression above.

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (0.034L × 6.2moles) / 5.4moles

V₂ = 0.2108molL / 5.4mol

V₂ = 0.039L

V₂ = 39 mL

Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

Learn more about Avogadro's law here: brainly.com/question/15613065

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6 0
2 years ago
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