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ikadub [295]
3 years ago
5

Simplify i99 each of the following powers if I.

Mathematics
2 answers:
liq [111]3 years ago
8 0

Answer:

bro..............what?

9966 [12]3 years ago
4 0

Answer:

-i

Step-by-step explanation:

answer is -i

You might be interested in
How many ounces are equivalent to 6 pounds?​
Dima020 [189]

Answer:

96

Step-by-step explanation:

1 pound is 16 ounces

6 pounds=x ounces

So we use the X to signal it's presence

1x16 is 16,

That means 16 ounces

6xP=Q

6x16 will give us our answer

Because it will tell us how many pounds there are since ounces is multiplied to get ounces.

6x16=96

P=16

Q=96

96 is our answer.

I hope this helps!!!!

If you need help, don't hesitate to ask!

I'm here until 2:30

May I please have brainliest?

5 0
3 years ago
What is lim x → 9+ ( x - 9/| 9 - x | )
SIZIF [17.4K]

Answer:

The answer is nonexistent

Step-by-step explanation:

6 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
The question is............
irina1246 [14]
A(n,s)=(ns^2)/(4tan(180/n)), n=number of sides, s=side length

A(8,4.6)=(8*4.6^2)/(4tan22.5)

A(8,4.6)=42.32/tan22.5 m  (exact)

A(8, 4.6)≈102.17 m^2  (to nearest hundredth of a square meter)
7 0
3 years ago
Pls help answer <br> I’m thinking it’s negative but I’m not sure.
Digiron [165]
Negative i believe is the correct answer
3 0
4 years ago
Read 2 more answers
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