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luda_lava [24]
3 years ago
8

Rivers chemustry class is doing an experiment in which

Mathematics
2 answers:
IRINA_888 [86]3 years ago
6 0
After you complete the sentence we'll comment on what your having trouble with.
dedylja [7]3 years ago
5 0
In which what? please finish the sentence.
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Which of the exponential growth functions has a multiplicative rate of change of 4? 2 f(x) X x f(x) 1 f(x) - 1 NT -1 -1 2 1 4 8
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2 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

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2 years ago
HELP HELP HELP HELP HELP HELP!!!!!
sesenic [268]

Answer:

..

Step-by-step explanation:

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6x 4y y 5 -2 3x 6 how can I solve this
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Answer:

Look below at the image I have provided for you <3

Step-by-step explanation:

I hope this helps!

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