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luda_lava [24]
3 years ago
8

Rivers chemustry class is doing an experiment in which

Mathematics
2 answers:
IRINA_888 [86]3 years ago
6 0
After you complete the sentence we'll comment on what your having trouble with.
dedylja [7]3 years ago
5 0
In which what? please finish the sentence.
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Write and solve an equation to find the number n.
garik1379 [7]
The unknown number is n. So n is the unknown variable in the equation.
In order to write an equation in which n is included we must know some dependence of n with other values.
We know that <span>the difference of three times a number and 44 is −19. So, we can write:
3*n-44=-19
3*n=-19+44
3*n=25
n=25/3


</span>
5 0
3 years ago
Values of 1/64 check all that apply
xenn [34]

Answer:

there r many values of such fractions just see whether one of it's multiple match with the options like

Step-by-step explanation:

4 0
3 years ago
What is 13.62 divided by -3.14?
Alex Ar [27]

Answer:

-4.3375796178343949044585987261146‬

Step-by-step explanation:

you can probably round it off but that is what my calculator gave me.

4 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
What is Nine sixteenths of 11 inches?
fenix001 [56]
<span>6.1875 inches would be 9 / 16 ths of 11 inches

</span>
4 0
3 years ago
Read 2 more answers
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