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3 years ago

15

Pls pls pls pls pls pls pls pls pls pls pls

2 answers:

Nikitich [7]3 years ago

5 0

I believe it would be 130 degrees

nekit [7.7K]3 years ago

5 0

It’s 130° because a straight line is 180° and 180-50 is 130

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Which angles are complementary to each other?

Mariulka [41]

Answer:

angle CDA and angle BDC

mark this as brainliest!

6 0

3 years ago

Read 2 more answers

Kyle is drawing a rectangle on the coordinate plane. Which coordinate pair could be Point M, the missing vertex of the rectangle

Leni [432]

Answer:

Step-by-step explanation:

5,2

3 0

4 years ago

PLEASE ILL MAKE BRAINIEST!!!

expeople1 [14]

Answer:

The area of rectangle BEFD is 180 square units.

Step-by-step explanation:

After checking the figure given, we have the following information:

$AD = 15$ , $AB = 12$ , $BC = 15$ , $CD = 12$

By Pythagorean Theorem, we determine the length of the line segment BD:

$BD = \sqrt{AB^{2}+AD^{2}}$ (1)

$BD = \sqrt{12^{2}+15^{2}}$

$BD = 3\sqrt{41}$

In addition, we know the following characteristics of the rectangle BEFD:

$BD = EF$ , $EF = EC + CF$ , $BE = FD$ (2), (3), (4)

By Pythagorean Theorem:

$BC^{2} = BE^{2}+EC^{2}$ (5)

$CD^{2} = CF^{2}+DF^{2}$ (6)

By (3), (4), (5) and (6):

$BC^{2} = BE^{2} + EC^{2}$ (7)

$CD^{2} = (EF-EC)^{2} + BE^{2}$ (8)

By (7) in (8):

$CD^{2} = (EF-EC)^{2}+ (BC^{2}-EC^{2})$

$CD^{2} = EF^{2}-2\cdot EF\cdot EC + EC^{2}+BC^{2}-EC^{2}$

$CD^{2} = EF^{2}-2\cdot EF\cdot EC +BC^{2}$

Then, we clear $EC$ :

$2\cdot EF\cdot EC = EF^{2} + BC^{2} - CD^{2}$

$EC = \frac{EF^{2}+BC^{2}-CD^{2}}{2\cdot EF}$

If we know that $EF = 3\sqrt{41}$ , $BC = 15$ and $CD = 12$ , then the length of the segment $EC$ is:

$EC = \frac{75\sqrt{41}}{41}$

And the length of the line segment $CF$ is:

$CF = EF - EC$

$CF = 3\sqrt{41}-\frac{75\sqrt{41}}{41}$

$CF = \frac{48\sqrt{41}}{41}$

And the length of the line segment $DF$ is determined by Pythagorean Theorem:

$FD = \sqrt{CD^{2}-CF^{2}}$

$FD = \sqrt{12^{2}-\left(\frac{48\sqrt{41}}{41} \right)^{2}}$

$FD = \frac{60\sqrt{41}}{41}$

And the area of the rectangle is determined by the following formula:

$A = FD\cdot EF$

$A = \left(\frac{60\sqrt{41}}{41} \right)\cdot (3\sqrt{41})$

$A = 180$

The area of rectangle BEFD is 180 square units.

4 0

3 years ago

The length of a rectangle is 10 inches longer than the width. The perimeter is 56 inches. Find the length and the width of the r

goldfiish [28.3K]

Answer:

$Length=19\,inches\\\\Width=9\,inches$

Step-by-step explanation:

Let, the length of the rectangle be 'L',

Width of the rectangle be 'W'

$L=(W+10)\,inches$

Perimeter of the rectangle= $56\,inches$

Perimeter of the rectangle= $2(Length+Width)$

$56=2(W+10+W)\\\\\dfrac{56}{2} =W+10+W\\\\28=2W+10\\\\28-10=2W\\\\18=2W\\\\W=\dfrac{18}{2}\\\\ W=9\,inches$

As,

$L=(W+10)\,inches$

$L=9+10\\\\L=19\,inches$

$Length=19\,inches\\\\Width=9\,inches$

7 0

4 years ago

Please help Z and Y

gizmo_the_mogwai [7]

Answer:

10=Z and 10=Y

Step-by-step explanation:

since it is a 45, 45, 90 triangle

both Z and Y will be the same length

the hypotenuse has a length of $x\sqrt{2}$ with x being the length of the legs

Since the length of this triangle's hypotenuse is $10\sqrt{2}$ the side length would be 10

Hope that helps :)

8 0

3 years ago