Answer:
<h2>

</h2>
Solution,
Let the points be A and B
A(-4 , 1)------>( X1, y1)
B(2,4)---------->( x2, y2)
Now,
Gradient:





Hope this helps...
Good luck on your assignment...
Hello there,
Part 1:
Perimeter of Red = 11+11+11+11
= 44
Perimeter of Blue= 6+6+6+6
= 24
Ratio: Red : Blue
44 : 24(divide by 4)
11 : 6
Part 2:
Area of Red= 11 x 11
= 121
Area of Blue= 6 x 6
= 36
Ratio: Red : Blue
121: 36
Hope this helps :))
~Top
Answer:
Test statistic = -2.25
P-value = 0.0199
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 450 gram
Sample mean,
= 441 grams
Sample size, n = 16
Alpha, α = 0.05
Sample variance = 256

First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Degree of freedom =

We can calculate the p-value from the table as:
P-value = 0.0199
Conclusion:
Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.
Thus, there is enough evidence to support the claim that the machine is under filling the bags .
Answer:
A) ![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The rotation matrix for a clockwise rotation through angle θ is given by ...
![M=\left[\begin{array}{cc}\cos{(\theta)}&-\sin{(\theta)}\\\sin{(\theta)}&\cos{(\theta)}\end{array}\right]](https://tex.z-dn.net/?f=M%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%7B%28%5Ctheta%29%7D%26-%5Csin%7B%28%5Ctheta%29%7D%5C%5C%5Csin%7B%28%5Ctheta%29%7D%26%5Ccos%7B%28%5Ctheta%29%7D%5Cend%7Barray%7D%5Cright%5D)
When θ = 90°, the matrix becomes the one in choice A).
Please note translations are just movements on a axis, they are not changing the length of a segment at all. In fact, only dilations change the figure. The length of E'F' is going to be the same as the length of EF.