All categories

3 years ago

A telephone pole were fixed 50m apart.how many poles were there in 26km??

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

There are 430 poles in a distance of 26km

You might be interested in

100 points + brainlest please help due today

Reptile [31]

Answer:

Use the formula for direct variation

Step-by-step explanation:

6 0

3 years ago

please help me with this math problem, the question is on the picture that i attached, ill mark brainliest if the answer is corr

dsp73

Answer:

cos z = 35 / 37

Step-by-step explanation:

cos z is the ratio of the adjacent side of a triangle (the side adjacent to angle z to the hypotenuse:

cos z = (adj. side) / (hypotenuse)

Here we have cos z = 35 / 37

7 0

3 years ago

Is this answer correct

Kobotan [32]

Yes, that looks right.

6 0

4 years ago

Solve the right triangle, ΔABC, for all the missing side and angles to the nearest tenth given sides a = 10.6 and b = 19.2.

Aliun [14]

Answer:

Part 1) $c=21.9\ units$

Part 2) $B=61.1\°$

Part 3) $A=28.9\°$

Part 4) $C=90\°$

Step-by-step explanation:

step 1

Find the length side c

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

substitute the given values

$c^{2}=10.6^{2}+19.2^{2}$

$c^{2}=481$

$c=21.9\ units$

step 2

Fin the measure of angle B

we know that

In the right triangle

$tan(B)=b/a$

substitute the given values

$tan(B)=19.2/10.6$

$B=arctan(19.2/10.6)=61.1\°$

step 3

Find the measure of angle A

we know that

The measure of interior angles in a triangle must be equal to 180 degrees

∠A+∠B+∠C=180°

Remember that in a right triangle the measure of angle C is 90 degrees

we have

$B=61.1\°$

$C=90\°$

substitute

$A+61.1\°+90\°=180\°$

$A=28.9\°$

4 0

3 years ago

Fayzansabeel is a very brainly user!!!

wariber [46]

Answer:

oh ok.. can i get ur intro??

3 0

2 years ago

Read 2 more answers

A telephone pole were fixed 50m apart.how many poles were there in 26km??​

A telephone pole were fixed 50m apart.how many poles were there in 26km??