![▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪](https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%20%20%7B%5Chuge%5Cmathfrak%7BAnswer%7D%7D%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA)
Here's the solution ~
The given points are : (-7 , -4) and (1 , 1)
now, let's use distance formula to find the distance between them !
![{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:\sqrt{(x_2 - x_1)² +( y_2 - y_1)² }](https://tex.z-dn.net/?f=%7B%20%5Cqquad%7B%20%5Csf%7B%20%5Cdashrightarrow%7D%7D%7D%20%20%5C%3A%20%20%5C%3A%20%5Csf%20%5C%3A%5Csqrt%7B%28x_2%20-%20x_1%29%C2%B2%20%2B%28%20y_2%20-%20y_1%29%C2%B2%20%7D%20)
![{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sqrt{( - 7 - 1) {}^{2} + ( - 4 - 1) {}^{2} }](https://tex.z-dn.net/?f=%7B%20%5Cqquad%7B%20%5Csf%7B%20%5Cdashrightarrow%7D%7D%7D%20%20%5C%3A%20%20%5C%3A%20%5Csf%20%5C%3A%20%5Csqrt%7B%28%20-%207%20-%201%29%20%7B%7D%5E%7B2%7D%20%20%2B%20%28%20-%204%20%20-%201%29%20%7B%7D%5E%7B2%7D%20%7D%20)
![{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sqrt{( - 8)² +( - 5)² }](https://tex.z-dn.net/?f=%7B%20%5Cqquad%7B%20%5Csf%7B%20%5Cdashrightarrow%7D%7D%7D%20%20%5C%3A%20%20%5C%3A%20%5Csf%20%5C%3A%20%5Csqrt%7B%28%20-%208%29%C2%B2%20%2B%28%20%20-%205%29%C2%B2%20%7D%20)
![{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sqrt{64 + 25}](https://tex.z-dn.net/?f=%7B%20%5Cqquad%7B%20%5Csf%7B%20%5Cdashrightarrow%7D%7D%7D%20%20%5C%3A%20%20%5C%3A%20%5Csf%20%5C%3A%20%5Csqrt%7B64%20%2B%2025%7D%20)
![{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \sqrt{89}](https://tex.z-dn.net/?f=%7B%20%5Cqquad%7B%20%5Csf%7B%20%5Cdashrightarrow%7D%7D%7D%20%20%5C%3A%20%20%5C%3A%20%5Csf%20%5C%3A%20%5Csqrt%7B89%7D%20)
Answer:
the correct answer would be 6 inches.
Step-by-step explanation:
12*.5=6
Answer: B
Step-by-step explanation:
The volume is (area of cross-section) x (length) .
-- The cross-section is a triangle. The area of a triangle is
Area = (1/2) (base) (height) .
In this one, the base is 9/4 m and the height is 3-1/3 m .
Area = (1/2) (9/4 m) (3-1/3 m)
Area = (1/2) (9/4) (10/3)
Area = 90/24 m² .
-- Volume = (area of cross-section) x (length)
Volume = (90/24 m²) x (7-1/3 m)
Volume = (90/24) x (22/3) m³
Volume = (1,980 / 72) m³
<em>Volume = 27.5 m³ </em>
Step-by-step explanation:
Answer to A square-based pyramid has a slant height of 10 meters and a side base of 16 meters. What is the surface area? by Janet Heberling https://www.quora.com/A-square-based-pyramid-has-a-slant-height-of-10-meters-and-a-side-base-of-16-meters-What-is-the-surface-area/answer/Janet-Heberling-1?ch=15&oid=253187394&share=f14a7431&srid=hdLI1f&target_type=answer