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dimaraw [331]
3 years ago
14

Use inductive reasoning to predict the most probable next number in each list.

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

  93

Step-by-step explanation:

First differences increase by 4 each time. The given numbers are a quadratic sequence that can be described by 2n² -2n +9. The 7th term would be 93.

_____

First differences are ...

  13-9 = 4, 21-13 = 8, 33-21 = 12, 49-33 = 16, 69-49 = 20

Second differences are ...

  8-4 = 4, 12-8 = 4, 16-12 = 4, 20-16 = 4

When second differences are constant, the sequence can be represented by a second-degree polynomial function. The leading coefficient is half the value of the second differences.

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Answer:

Hence, the p-value ( 0.699986) > 0.05,  FAIL TO REJECT THE NULL HYPOTHESIS

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Step-by-step explanation:

Given the data in the question;

Starting position:     1     2     3     4     5     6

# of Winners:         25   22   18   19    21   15

Mean x" (E) = (25+22+18+19+21+15)/6 = 120/6 = 20

Observed/Expected value table;

O       E            ((O-E)²) / E

25    20            1.25

22    20            0.2

18     20            0.2

19     20           0.05

21     20           0.05

15     20           1.25

∑                         3

so using chi square = ∑(((O-E)²) / E) = 3

DF = n-1 = 6-1 = 5

then, the critical chi square value is;

significance level = 0.05

chi square( critical ) = 11.07049769

from table;

p - value = 0.699986

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