Let's have Steve's age be <em>x</em><em />, and his father's age be <em>f</em>
Then, we can set up equations
Steve is one-fourth as old as his father goes to an equation as x=(1/4)f
In five years (x+5), Steve will be one-third as old as his father will be (f+5). This goes to an equation as x+5=(1/3)(f+5)
We can then solve the first equation for either variable (I will be doing f), and plug it in for a system of equations.
x=(1/4)f
4x=f ← plug that in for f in the next equation
x+5 = (1/3)(4x+5) ← Solve this for x
3(x+5)=4x+5
3x+15=4x+5
3x+10=4x
10=1x
x=10
Therefore, Steve's age is 10. His father's age is <em>f=4x, </em>plug in 10 for x, and his father's age is 40
Answer:
all real numbers
Step-by-step explanation:
There are no radicals or fractions involved, so the domain is
Answer:
Step-by-step explanation:
Divide both sides by 
:
Simplify:
5x+3y+6x+9y
All you'd need to do is combine like terms. So add 5x to 6x and add 3y to 9y.
(5x+6x)+(3y+9y)
Final Answer: 11x + 12y
Answer:
Step-by-step explanation:
Charging by the quarter mile is for purpose of making that particular taxi service seem cheaper than the others when they post a per mile charge. If this taxi company is charging .50 per 1/4 mile, they are charging $2 per mile. So we will base our equation on the per mile charge, not the per quarter-mile charge. If x is the number of mile driven (our uknown), and we have a flat fee of $2.50 regardless of how many miles we are driven, the cost function in terms of miles is
C(x) = 2x + 2.50
If we are driven 5 miles, then
C(5) = 2(5) + 2.50 so
C(5) = 10 + 2.50 and
C(5) = $12.50
It would cost $12.50 to be driven 5 miles
