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Inessa05 [86]
3 years ago
12

AB parallel to CD and AC=BC find d​

Mathematics
1 answer:
kirill115 [55]3 years ago
3 0

Answer:

58\int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right.  \lim_{n \to \infty} a_n

Step-by-step explanation:

You might be interested in
100 POINTS IF YOU GUESS RIGHT PLEASE HELP
soldi70 [24.7K]

Answer:

  • 5 and 3

Step-by-step explanation:

Let the numbers be x and y.

<u>We have:</u>

  • x + y = 8
  • x - y = 2

<u>Sum the two and find x:</u>

  • 2x = 10
  • x = 5

<u>Find y:</u>

  • y = 5 - 2
  • y = 3
6 0
3 years ago
If x=-4 and y=6, then xy-3=
Anna11 [10]

Answer:

-12

Step-by-step explanation:

We start with the equation: xy-3x

Substitute the variables: (-4)(6)-3(-4)

Solve using order of operations (start with multiplication): (-24)-(-12)

And then addition/subtration: (-24)-(-12)=-12

3 0
3 years ago
Use the distributive property to rewrite and find 4 x (25 + 4). Thanks.
sesenic [268]
116 , <span><span>(4 * 25) + ( 4 * 4 )
</span>4 x (25 + 4)
4 * 25
4 * 4
(4 * 25) + ( 4 * 4 ) = Distributive Property
</span><span><span>4 * 25 = 100
4 * 4  = 16</span>
100 + 16 = 116


</span>

5 0
3 years ago
Read 2 more answers
Mr. Thompson, a retiree, looks at his check register.
sukhopar [10]

As given,

Weekly rent of Mr. Thomson is = $104.92

Part A: What is Mr. Thompson's yearly rent (using 52 weeks)?

Rent for 1 week = 104.92

Rent for 52 weeks = 104.92\times52 = $5455.84

Part B: What was the average grocery expense in this time period?

Mr. Thomson purchased groceries on 2/18 for $33.45 and on 3/5 for $28.56

Hence average grocery expense is = \frac{33.45+28.56}{2}

= $31 per week or $62.01 per month

Part C: Mr. Thompson estimates his yearly expense for groceries to be:

The monthly expense for groceries is = $62.01

So yearly expense will be = 62.01\times12 = $744.12

4 0
3 years ago
Major help and if you can, please explain how you got your answer
hjlf
The correct answer is:  [A]:  " 384 in² " .
_______________________________________________________

Explanation:
______________________________________________________
The formula for the surface area of a cube is:
______________________________________________________

             →   A   =   6a²  ;
______________________________________________________             →   in which:  
______________________________________________________
                            A  =  surface area of the cube— for which we shall solve ; 
                                               (in "square units" ; or, " in² " ; in our case) ; 

                            a = side length = " 8 in " (given); 
    
   →  Note:  A cube has all equal side lengths.

   →  The "6" in the formula accounts for "6 sides" of a cube.

_______________________________________________________

→  To solve for the surface area of the cube; plug in our known value(s);
                &  solve;  as follows:
_______________________________________________________
                          →  A  =  6 a²  ;

                                    =  6 * (8 in)²  ;

                                    =  6 * 8² * in² ;

                                    =  6 * 8 * 8 * in² ; 

                                    =  48 * 8 * in² ; 

                                    =  384  in²  ;
_______________________________________________________
The answer is:  " 384 in² " ;  

→  which is:  Answer choice:  [A]:  " 384 in² " .
_______________________________________________________
8 0
4 years ago
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