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Alex787 [66]
3 years ago
11

Pls help!!! will give brainy!!!

Engineering
1 answer:
adell [148]3 years ago
8 0

Answer:

Robots Manager

someome with this office might just be there to keep tracks of robots

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The capacity of a battery is 1800 mAh and its OCV is 3.9 V. a) Two batteries are placed in series. What is the combined battery
Lynna [10]

Answer:

capacity  = 0.555 mAh

capacity  = 3600 mAh

Explanation:

given data

battery = 1800 mAh

OCV = 3.9 V

solution

we get here capacity when it is in series

so here Q = 2C  

capacity  = 2 × ampere × second   ...............1

put here value and we get

and 1 Ah = 3600 C

capacity  = \frac{2}{3600}

capacity  = 0.555 mAh

and

when it is in parallel than capacity will be

capacity = Q1 +Q2   ...............2

capacity  = 1800 + 1800

capacity  = 3600 mAh

3 0
4 years ago
What is the term RF exiciter?
Sati [7]
The exciter provides fully coherent receiver local oscillator signals at radar frequency band as well as requisite, auxiliary high frequency clock signals. The exciter function is divided into an internal frequency synthesizer and an upconverter.

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7 0
3 years ago
Does anybody want 20 points? They're free get 'em while ya can...
DedPeter [7]

Answer:

hi

Explanation:

4 0
3 years ago
Read 2 more answers
Refrigerant 134a is the working fluid in a vaporcompression heat pump that provides 35 kW to heat a dwelling on a day when the o
Dennis_Churaev [7]

Answer:

Hello, dear.

For the answer please see the explanation below.

Explanation:

The compressor power is:

2.212kW

(b) The refrigeration capacity is:

3.62 tons

(c) The coefficient of performance is:

5.75

5 0
4 years ago
Determine the change in the enthalpy of helium, in kJ/kg, as it undergoes a change of state from 100 kPa and 20 oC to 600 kPa an
MatroZZZ [7]

Answer:

The change in enthalpy of helium is 4073.86kJ/kg

Explanation:

∆H = Cp(T2 - T1)

Cp = 3.5R = 3.5×8.314 = 29.099kJ/kgmolK ÷ 2 (1kgmol of helium = 2kg of helium) = 14.5495kJ/kgK, T2 = 300°C = 300+273K = 573K, T1 = 20°C = 20+273K = 293K

∆H = 14.5495kJ/kgK(573K - 293K) = 14.5495kJ/kgK × 280K = 4073.86kJ/kg

7 0
4 years ago
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