Answer:
Explanation:
Attached is the solution to the question
Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Explanation:
F, W and B are the fresh feed, brine and total water obtained
w = 2 x 10^4 L/h
we know that
F = W + B
we substitute
F = 2 x 10^4 + B
F = 20000 + B .................EQUA 1
solute
0.035F = 0.05B
B = 0.035F/0.05
B = 0.7F
now we substitute value of B in equation 1
F = 20000 + 0.7F
0.3F = 20000
F = 20000/0.3
F = 66666.67 kg/hr
B = 0.7F
B = 0.7 * F
B = 0.7 * 66666.67
B = 46,666.669 kg/hr
the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Answer:
Option (c) and option (d)
Explanation:
Eutectic system is one in which a solid and homogeneous mixture of two or more substances resulting in the formation of super lattice is formed which can melt or solidify at a temperature lower than the melting point of any individual metal.
Eutectic alloys are those which have its components mixed in a specific ratio.
It is the composition in an alloy system for which both the liquidus and solidus temperatures are equal.
Eutectic alloys have the composition in which the melting point of the metal is lower than the other alloy composition.
Answer:
The solution code is written in Java.
- public class Movie {
- private double [][] seats = new double[5][5];
- private double totalSales;
-
- public Movie(){
-
- for(int i= 0; i < this.seats.length; i++){
- for(int j = 0; j < this.seats[i].length; j++){
- this.seats[i][j] = 12;
- }
- }
-
- this.totalSales = 0;
- }
-
- public boolean bookSeat(int i, int j)
- {
- if(this.seats[i][j] != 0){
- this.totalSales += this.seats[i][j];
- this.seats[i][j] = 0;
- return true;
- }else{
- return false;
- }
-
- }
- }
Explanation:
The method, bookSeat(), as required by the question is presented from Line 16 - 26 as part of the public method in a class <em>Movie</em>. This method take row,<em> i</em>, and column,<em> j</em>, as input.
By presuming the seats is an two-dimensional array with all its elements are initialized 12 (Line 7 - 10). This means we presume the movie ticket price for all the seats are $12, for simplicity.
When the<em> bookSeat() </em>method is invoked, it will check if the current price of seats at row-i and column-i is 0. If not, the current price, will be added to the <em>totalSales </em>(Line 19)<em> </em>and then set the price to 0 (Line 20) and return <em>true</em> since the ticket is successfully sold (Line 21). If it has already been sold, return <em>false</em> (Line 23).
Answer:
a) The additional time required for the truck to stop is <u>8.5 seconds</u>
b) The additional distance traveled by the truck is <u>230.05 ft</u>
Explanation:
Since the acceleration is constant, the average speed is:
(final speed - initial speed) / 2 = 0.75 v0
Since travelling at this speed for 8.5 seconds causes the vehicle to travel 690 ft, we can solve for v0:
0.75v0 * 8.5 = 690
v0 = 108.24 ft/s
The speed after 8.5 seconds is: 108.24 / 2 = 54.12 ft/s
We can now use the following equation to solve for acceleration:
a = -6.367 m/s^2
Additional time taken to decelerate: 54.12/6.367 = 8.5 seconds
Total distance traveled:
0 - 108.24^2 = 2 * (-6.367) * s
solving for s we get total distance traveled = 920.05 ft
Additional Distance Traveled: 920.05 - 690 = 230.05 ft
