Question

A 4 standard type L copper tube conveys propyl alcohol at 151/s. The pipe is laid out horizontally. It is 60 îm long. Calculáte the pressure drop

Answer 1

Answer:

pressure drop is 17.19 MPa

Explanation:

given data

flow rate = 15 l/s = 0.015 m³/s

length of pipe = 60 m

4 standard type L copper tube

to find out

pressure drop

solution

we know that from 4 standard type L copper tube

diameter of pipe is 8 mm = 0.008 m

and viscosity of propyl alcohol is = 0.00192 N-s/m²

so

pressure drop along horizontal pipe formula is

P1-P2 = $\frac{128*\mu*L*Q}{\pi D^4}$     .................1

here L is length and Q is flow rate and D is diameter and µ is viscosity so

pressure drop ( P1 -P2 ) is

P1-P2 = $\frac{128*\mu*L*Q}{\pi D^4}$

P1-P2 = $\frac{128*0.00192*60*0.015}{\pi (0.008)^4}$

P1-P2 = 17197452.23 N/m²

so pressure drop is 17.19 MPa