I assume you mean:
[x^(5/6)]/[x^(1/6)]
The rule for dividing similar bases with different exponents is:
(a^b)/(a^c)=a^(b-c)
In this case we have:
x^(5/6-1/6)
x^(4/6)
x^(2/3)
First round up 249.99 to 250.00
Then change the 4% into a decimal= 1.04
Now multiply so the equation is= 250 x 1.04 =
$260 as your answer!
<span>x² + y² + 14x − 4y − 28 = 0
x² +14x +y² - 4y =28
x²+2*7x +7² -7² + y² - 2*2y +2² - 2² = 28
(x+7)² + (y-2)² -7²-2² =28
</span>(x+7)² + (y-2)²=28+49+4
(x+7)² + (y-2)² =81 is the answer.
Answer:
The question is incomplete, the complete question is "Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. See Example 9.
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Step-by-step explanation:
From the general properties or laws of logarithm, we have the

where both log are now express in the natural logarithm base.
i.e 
hence we can express our
.
the value of ln7 is 1.9459 and ln4 is 1.3863
Hence
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First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11
Fourth, 15+-20= -5
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16
Last, do 8x/8x and 16/8x
The answer is x=2