Prokaryotic translation Eukaryotic translation
1. The mRNA of Prokaryotic translation is monocistronic while the mRNA of Eukaryotic translation is known to be polycistronic.
2. In Prokaryotic translation, transcription and translation occurs at the same time in the cytoplasm while transcription occurs at the nucleus, as translation is seen at the cytoplasm of Eukaryotic translation
3. Prokaryotic translation do not undergo post-transcriptional modification, prior its translation of mRNA. Eukaryotic translation produces pre-mRNA from transcription as it undergo modification into mRNA before it's being transported to the cytoplasm for translation.
4. Prokaryotic translation its simple with only one initiation mechanism and a few amount of factors for the whole translation Unlike Euaryotic translation that possess two initiation mechanisms: cap- dependent and cap-independent plus varying factors and enzymes for the whole translation.
5
Prokaryotes can translate 20 amino acids per second and requires 2 release factors-RF1 and RF2
Eukaryotes can translate only one amino acid per second and requires only one release factor-eRF1
6
Post-translational modification takes place in the cytoplasm.
It can take place in Endoplasmic reticulum or Golgi bodies or cytoplasm
Groundnut is nuts. It is another word for peanuts
It's the stimulus because that's what triggers the salivation which is the reaction
Answer:
<em>experimental group</em>
Explanation:
In scientific experiments, an experimental group can be described as a group which is under study. In this group, an independent and dependent variable is present. An independent variable can be described as the factor which changes either naturally or which is being changed by the researcher. A dependent variable can be described as the variable which is under study and it might be dependent on the independent variable.
Answer:
volume of 2% saline (V₁) = 0.25ml
volume of water = 4.75ml
Explanation:
The requirement in the question is to obtain 0.1% of NaCl from 2% NaCl, and the process is dilution. The general dilution equation is guven by:
C₁V₁ = C₂V₂
where:
C₁ = initial concentration = 2%
V₁ = initial volume = ?
C₂ = final concentration = 0.1%
V₂ = final volume = 5ml
C₁V₁ = C₂V₂
calculating for V₁
∴ V₁ = (C₂V₂) ÷ C₁
= (0.1% × 5) ÷ 2%
V₁ = 0.25ml
Now, let us calculate the volume of water needed:
V₁ + Volume of water = V₂ (volume of 0.1% NaCl)
0.25 + volume of water = 5
volume of water = 5 - 0.25
volume of water = 4.75ml
