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OLga [1]
3 years ago
15

Write a standard form equation...

Mathematics
1 answer:
Alchen [17]3 years ago
4 0
I know the answer isnt A
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Which equation can be simplified to find the inverse of y = 5x2 + 10?
zmey [24]

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

Step-by-step explanation:

interchanging the variables

x = 5y^2 + 10

5y^2 +10 = x

5y^2 = x - 10

dividing by 5

5y^2/5 = x/5 + -10/5

y^2 = x/5 + - 10/5

y^2 = x/5 - 2

y = 5 (x-10) 0/5 (sq.rt)

g(5x^2 + 10) = 5x/5

g(5x^2 + 10) = x

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

5 0
2 years ago
Read 2 more answers
Your lunch account has $23 and you spend $2.20 each day on your lunch write an equation for the line
-BARSIC- [3]

Answer:

Assuming you mean until the lunch money balance runs out,

$2.20x = $23

Step-by-step explanation:

You spend $2.20 every day.  If you are trying to find how many days until the lunch balance runs out, you need to put in X as your variable.

The last step is to set it equal to $23 dollars to be able to factor out the answer.


Hope this Helped!

4 0
3 years ago
Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=
Debora [2.8K]
The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
3 0
3 years ago
3/4 3√128. simplify?<br>kindly<br>​
lisov135 [29]

Answer:  3∛2

<u>Step-by-step explanation:</u>

First, factor 128 .... you need three common factors to bring one on the outside of the radical.

\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }

6 0
3 years ago
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What is the solution to the system of equation?
Sergeu [11.5K]
The correct answer is (0, 3)
3 0
2 years ago
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